Write an SQL CREATE TABLE statement to create the PET_OWNER table, withOwnerID as a surrogate key. Justify your choices of column properties.The following table schema for the PET_2 table is an alternate version of the PET table—use it to answer review questions 3.11 and 3.12:PET_2 (PetName, PetType, PetBreed, PetDOB, OwnerID)

Write SQL statements to create at the two tables for the database. The tables must have at least three relevant columns with appropriate types, a primary key and at least one table should have a foreign key and the related foreign key constraints. CREATE TABLE students ( Student_id int NOT NULL PRIMARY KEY, Stud_firstname VARCHAR(30) NOT NULL, Stud_lastname VARCHAR(30) NOT NULL, Stud_email VARCHAR(80) NOT NULL UNIQUE advisor_id int, );   create table advisor ( advisor_id int not null primary key, stud_id int, adv_firstname varchar(30), adv_lastname varchar(30), foreign key(student_id) references students(student_id) );   [keep getting error, need help correcting]

Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENANCE_TYPE_ID should be foreign keys to their original tables. Cascade update and cascade delete the foreign keys. Create a new table to store maintenance operations     Test Query DESCRIBE MAINTENANCES Expected Results Field Type Null Key Default Extra CAR_ID char(5) NO PRI NULL   MAINTENANCE_TYPE_ID char(5) NO PRI NULL   MAINTENANCE_DUE date NO PRI NULL

Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENACNE_TYPE_ID should be foreign keys to their original tables. Cascade update and cascade delete the foreign keys.   Answer in MYSQL please

Based on the following authorication commands (ordered from 1 to 4), which of the following privileges is true, assuming that Ali is the owner of the database? Order By Ali 1 2 3 4 Select one: Omar Ali Ali Command Grant Select on Employee to Omar with grant option; Grant Select on Employee to Samer with grant option; Grant Update on Employee to Omar with grant option; Revoke Select on Employee From Omar Cascade; a) Ali and Omar have Update privilege on employee Ali has select privilege on employee b) Ali and Omar have Update privilege on employee Omar and Samer have select privilege on employee elect c) Ali and Omar have Update privilege on employee Ali and Omar have select privilege on employee d) Ali and Omar have Update privilege on employee Ali, Omar and Samer have select privilege on employee

My SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…

Assistance with SQL statements   Previous code; CREATE TABLE Lab4program_piershed (  code VARCHAR(5) PRIMARY KEY,  name VARCHAR(20),  tel VARCHAR(20));CREATE TABLE Lab4course_xxxx (  cid INT PRIMARY KEY,  name VARCHAR(20),  credits INT,  mycode VARCHAR(5),  FOREIGN KEY (mycode) REFERENCES Lab4program_xxxx(code)); 1. Insert 3 records into your Lab4program_xxxx table. The code should be "CPS", "TECH", "MATH", or "BIO". Please copy/paste your SQL statements with the output message in the text that shows you successfully insert 3 records to your table. 2. Insert 4 records into your Lab4course_xxxx table with at least 2 different mycode. Please copy/paste your SQL statements with the output message in the text that shows you successfully insert 4 records to your table.