Write a public method named findSum that takes a a parameter named n of type int. If n is less than 1 the method returns -1 otherwise it returns a number that is the result of applying the following formula to i values ranging from 1 to n: Note :E is the symbol for summation.
Write a public method named findSum that takes a a parameter named n of type int. If n is less than 1 the method returns -1 otherwise it returns a number that is the result of applying the following formula to i values ranging from 1 to n: Note :E is the symbol for summation.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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java
![**Creating the `findSum` Method**
**Objective:** Write a public method named `findSum` that takes a parameter named `n` of type `int`. If `n` is less than 1, the method returns -1; otherwise, it returns a number that is the result of applying the following formula to `i` values ranging from 1 to `n`.
**Note:** The symbol Σ (summation) is used in the formula.
**Formula Representation:**
\[ \sum_{i=1}^{n} \left( \frac{n(n+1)}{2} \right) \]
- **Explanation of the Formula:**
- The formula provided within the summation symbol (Σ) calculates the sum of the first `n` natural numbers.
- The term \(\frac{n(n+1)}{2}\) is derived from the arithmetic series sum formula for the first `n` natural numbers.
Here is a breakdown of the formula:
- **Summation (Σ):** This notation indicates that you sum the values of the given expression for `i` ranging from 1 to `n`.
- **Expression:** \(\frac{n(n+1)}{2}\)
- `n` is the given number.
- The numerator `n(n+1)` calculates the product of `n` and `n+1`.
- Dividing by 2 gives the sum of the first `n` natural numbers.
**Instructions for Implementation:**
- **Step 1:** First, check if `n` is less than 1. If so, return -1.
- **Step 2:** Otherwise, calculate the sum using the formula \(\frac{n(n+1)}{2}\).
- **Step 3:** Return the computed sum.
By implementing these steps, the `findSum` method will accurately compute the required sum or return -1 if the input is invalid (i.e., less than 1).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e6f6223-c696-4938-9015-1aa854831435%2Fb0102d38-3972-46e3-884b-4a6ab268becd%2F06jc7z_processed.png&w=3840&q=75)
Transcribed Image Text:**Creating the `findSum` Method**
**Objective:** Write a public method named `findSum` that takes a parameter named `n` of type `int`. If `n` is less than 1, the method returns -1; otherwise, it returns a number that is the result of applying the following formula to `i` values ranging from 1 to `n`.
**Note:** The symbol Σ (summation) is used in the formula.
**Formula Representation:**
\[ \sum_{i=1}^{n} \left( \frac{n(n+1)}{2} \right) \]
- **Explanation of the Formula:**
- The formula provided within the summation symbol (Σ) calculates the sum of the first `n` natural numbers.
- The term \(\frac{n(n+1)}{2}\) is derived from the arithmetic series sum formula for the first `n` natural numbers.
Here is a breakdown of the formula:
- **Summation (Σ):** This notation indicates that you sum the values of the given expression for `i` ranging from 1 to `n`.
- **Expression:** \(\frac{n(n+1)}{2}\)
- `n` is the given number.
- The numerator `n(n+1)` calculates the product of `n` and `n+1`.
- Dividing by 2 gives the sum of the first `n` natural numbers.
**Instructions for Implementation:**
- **Step 1:** First, check if `n` is less than 1. If so, return -1.
- **Step 2:** Otherwise, calculate the sum using the formula \(\frac{n(n+1)}{2}\).
- **Step 3:** Return the computed sum.
By implementing these steps, the `findSum` method will accurately compute the required sum or return -1 if the input is invalid (i.e., less than 1).
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