Write a program that reads in five integers and determines and prints the largest and the smallest integers in the group. Use C language and in C++
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- Please code in python Forbidden concepts: recursion, custom classes Create a program that takes a university student’s name, their 1st parent’s income, and their second parent’s income. If the average income between the parents is $40,000 or below, then it would put them into a Tuition Grant list. If it’s above, then it would be a Full Tuition Required list. Once the university admission officer has completed inputting all the students, the program will end and print out the two lists.Assignment for Computer Architecture: N Factual by Recusion *please have comments in the code* You are to write a program in MIPS that computes N! using recursion. Remember N! is the product of all the numbers from 1 to N inclusive, that is 1 x 2 x 3 x (N – 1) x N. It is defined as 1 for N = 0 and is undefined for values less than 0. The programs first requests the user to input the value of N (display a prompt first so the user knows what to do). If the input value is less than 0, the program is to display “N! undefined for values less than 0” and then requests the user to input the value of N again. If the value input is non-negative, it is to compute N! using a recursive function, that is one that calls itself. You are to have your name, the assignment number, and a brief description of the program in comments at the top of your program. Since this is an assembly language program, I expect to see comments on almost every line of code in the program. Also make the…def main(): x = 1 y = 2 swap(x, y) print(x, y) def swap(s1, s2): temp = s1 s1 = s2 s2= temp main() Modify the code so that it actually swaps the values of x and y, without using the temp variable in the swap function.
- Non dynamic.arrays are allocated at runtime where dynamic arrays are allocated at compile time. True False Question 4 There are other ways to end a loop other than just the loop condition evaluating to false. True FalsePython please prime_test.py: def is_prime(num):#ADD CODE to return True if num is prime; False if notdef main():#ADD CODE to call is_prime() for integers 1-100# and print the ones that are primemain()Consider the following pseudo code, Method func() { PRINT “This is recursive function" func() } Method main( { func() } What will happen when the above snippet is executed?
- English Language Calculator Build a simple “English Language” calculator that does the following: Takes three inputs from the keyboard Two of the inputs are single-digit numbers (0 to 9) The third input is a char from the keyboard, representing one of the five operations from the keyboard: + (addition) - (subtraction) * (multiplication) / (division) ^ (exponentiation) Output the description of the operation in plain English, as well as the numeric result Input and Output Instruction for the Calculator If the two input numbers are 5 and 3, and the operation is *, then the output should be five multiplied by three is 15 Note that the result is given as a number, not a word. If the two numbers are 2 and 9, and the operation is -, then the output should be two minus nine is -7 If the two numbers are 5 and 2, and the operation is ^, then the output should be five to the power two is 25 Hint: To perform the exponentiation, use the pow method of the Math class. If the two…*please help in java* Array testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8. import java.util.Scanner; public class SumOfExcess {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int[] testGrades = new int[NUM_VALS];int i;int sumExtra = -9999; // Assign sumExtra with 0 before your for loop for (i = 0; i < testGrades.length; ++i) {testGrades[i] = scnr.nextInt();} // your answer goes here// System.out.println("sumExtra: " + sumExtra);}}Using the starter code below, write a program that asks a user for two points (x1, y1) and (x2, y2), then computes the area of the circle for which (x1, y1) is the center and (x2, y2) is on the circle's perimeter. The program should define and use 3 functions: distance(x1, y1, x2, y2): computes and returns the distance between two points • area(r): computes and returns the area of a circle with radius r • main(): asks user for input, calls the other functions, and prints the answer. The input and output of the program should look similar to this: X for center point: 0 Y for center point: 0 X for perimeter point: 1 Y for perimeter point: 1 Area of circle centered at (0.0, 0.0) with radius 1.414213 is 6.283185. Hint 1: Area of a circle = n? Hint2: Distance between 2 points = sqrt(x2-X12 + (Y2 - Y1)²) Starter code: import math def distance(x1, y1, x2, y2): #Add code to compute and return distance between (x1, y1) and (x2, y2) def area(r): #Add code to compute and return area of circle…
- [2, 4, 5, 8] input () while user_input != 'end': numbers = user_input try: = #Possible ValueError diviforint (user_input) if divisor > 20: #Possible NameError # compute() is not defined result = compute (result) elif divisor < 0: # Possible IndexError result = else: print ('OK') numbers [divisor] # Possible ZeroDivisionError result = 20 // divisor print (result, end-' ') except (ValueError, ZeroDivisionError): print ('r', end=' ') except (NameError, IndexError) : print ('s', end=' ') input () user input Type the program's output = # // truncates to an integer Input nine -10 0 2 -2 95 end Output 0Q1:- Passing by reference (z, j )using pointers when a= 54 , b=45 show me (1) a ,b before swap.(2)a,b after swap. call me your status. * 1 Add file. Convert the following pseudo code into assembly codo- (//' represents-comments). // Each element is 1 Byte long // Each element is 1 Byte long arrayl 13h, 14h, 15h, 16h array2 12h, 13h, 14h, 15h // lengthl is a Symbolic constant // length2 is a Symbolic constant // this variable is 1 byte long initialized with 30 lengthl = number of items in Arrayl. length2 = number of items in Array2 samplel = 30h sample2 = 5h. // this variable is 1 byte long 1 byte long variable maxlength = max of lengthl and length2. // maxlength is // this is a variable initialized with 0 index = 0. While ( If (arrayl [index] > array2[index] index < maxlength ){ * samplel) / (array2[index] expl = (arrayl[index] only store the quotient of the division in expl and expl is 7/16 bit long variable Sample2) else expl = 0 index = index + 1 }