Write a function size_t line Length (char* string) that returns the index of the first instance of \n in string. In other words, find the length of the first line of the string. You can be sure string will contain a '\n' before it ends. You may not use any string library functions. For example: Test Result printf("%zu\n", lineLength ("ABC\nDE")); 3

Write a function size_t line Length (char* string) that returns the index of the first instance of \n in string. In other words, find the length of the first line of the string. You can be sure string will contain a '\n' before it ends. You may not use any string library functions. For example: Test Result printf("%zu\n", lineLength ("ABC\nDE")); 3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement a function, countVowels, which takes in a string and counts the number of vowels that are contained within it. Make sure that both capital vowels and lowercase vowels are counted. Your starter code contains a main function, which asks for user input and outputs the number of vowels. You will need to implement the user input for the string. Sample Runs (user input is italicized and underlined): Enter a phrase: Hello World!Number of vowels: 3 Enter a phrase: PROGRAMMING IS EXCELLENT.Number of vowels: 7 #include <string>#include <iostream>using namespace std; int countVowels(string word); int main(){ string phrase; cout << "Enter a phrase: "; // To do: implement user input cout << "Number of vowels: " << countVowels(phrase) << endl;} // To do: Implement countVowels int countVowels(string word){}
pls use pyhton.. thanks for answer
Create a function that takes a string and returns the number of alphanumeric characters that occur more than once. Examples duplicateCount("abcde") duplicateCount("aabbcde") → 2 duplicateCount("Indivisibilities") - duplicateCount("Aa") 0 // Case sensitive N
Complete the scramble_text() function that takes a single string parameter text. The function returns a new string consisting of the characters in text scrambled order - every pair of characters have their positions swapped. You can assume that the parameter text will have a length of at least 1. For strings with an odd length, the last character remains unchanged in the scrambled text. Some examples of the function being called are shown below. For example: Test text = "I". print (f"{text} --scramble--> {scramble_text (text)}") text = "Hello" print (f"{text} --scramble--> {scramble_text (text)}") text = "superb" print (f"{text} --scramble--> {scramble_text (text)}") Result I --scramble--> I Hello --scramble--> eHllo superb --scramble--> usepbr
code should be python: write a function that allows the input of a list of strings as its only parameter. Inside the body of the function find the first palindromic word and return it. If there is no such word, it should return an empty string. A string is palindromic if it reads the same forward and backward so for example If we call the function with [“horse”, “rat”, “roar”, “dad”, “mom”], the returned value should be “dad”. Note that “mom” is also a palindrome, but it is not the first one.
1. a.Palindromes Complete the function palindrome(String text). Return true if text is a palindrome; if the word is identical forward and backward. Otherwise, return false. Example: palindrome(“racecar”) == true palindrome(“kayaks”) == false See main() for more examples. You can use text.charAt(i) to find the character at index i of text. Use recursion. palindrome() should call itself. No loops allowed. b. Complete the function nestedBrackets(String s). This function should find properly nested brackets within s. Return true if brackets are opened and closed correctly, and false otherwise. Single pairs and nested pairs are valid. For example: z[z]z, [zz[zz]z], [z[[z]zzz]], zzzzz Incorrect pairings and multiple separate pairs are not valid. For example: zz[zz, ]zzz[, [zzz][z], [z[z][z]z] See main() for more examples. nestedBrackets() should call firstIndexOf() and lastIndexOf() to help you solve the problem. Use recursion. nestedBrackets() should call itself. No loops…
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in the C++ version please suppose to have a score corresponding with probabilities at the end and do not use the count[] function. Please explain the detail when coding. DO NOT USE ARRAY. The game of Pig The game of Pig is a dice game with simple rules: Two players race to reach 100 points. Each turn, a player repeatedly rolls a die until either a 1 ("pig") is rolled or the player holds and scores the sum of the rolls (i.e. the turn total). At any time during a player's turn, the player is faced with two decisions: roll - if the player rolls 1: the player scores nothing and it becomes the opponents turn. 2 - 6: the number is added to the player's turn total and the player's turn continues. hold - The turn total is added to the player's score and it becomes the opponent's turn. This game is a game of probability. Players can use their knowledge of probabilities to make an educated game decision. Assignment specifications Hold-at-20 means that the player will choose to roll…
in python pls
Consider the following line of code: X = new int*[n]; What should the type of x be? O int O int* O int** O int& O None of the above
needed solution in js
def reverse_sentence(s: str) -> str:"""This means that in the string 'ATest string!', there are in fact only twowords: 'A' and 'Test string!'. Again, keep in mind that words start with acapital letter and continue until the next capital letter or the end of thestring, which is why we consider 'Test string!' as one word.This function will reverse each word found in the string, and return a newstring with the reversed words, as illustrated in the doctest below.>>> reverse_sentence('ATest string!')'A!gnirts tseT'""" please don't use any list function or import just basic if and loop function and also please do this code in python