Write a function named oddLessEven that returns the sum of odd digits minus even digits in a positive integer input. Example: oddLessEven programme. (Submit a single C++ file with the main function and your oddLessEven function.) int main() { cout << oddLessEven(23) << endl; // prints 1 cout << oddLessEven(1234); // prints -2 cout << oddLessEven(777); // prints 21 return 0; }

write a pseudo code for the C++ program below: The C++ code is given below :   //C++ Code   #include<iostream>#include<fstream>using namespace std;/*Create a global variable of type ofstream for the output file*/ofstream outfile; /** This function asks the user for the number of employees in the company. This value should be returned as an int. The function accepts no arguments (No parameter/input).*/int NumOfEmployees();/** accepts an argument of type int for the number of employees in the company and returns the total of missed days as an int. This function should do the following:Asks the user to enter the following information for each employee:The employee number (ID) (Assume the employee number is 4 digits or fewer, but don't validate it).The number of days that employee missed during the past year.Writes each employee number (ID) and the number of days missed to the output file */int TotDaysAbsent(int numberOfEmployees);/* calculates the average number of days…

Code the C++ function given below: