Would you use the same formula to find the width of each slit in a double slit difraction?

Please help ASAP with hand written solution Light hits a double slit, with a spacing of 178 μm. The 2nd dark spot is located exactly 7.78 cm from the central maximum. a) If light with a wavelength of 477 nm was used, how far away was the screen in metres? b) Also, find the angle made to the 3rd bright spot to the left of the central maximum. Include a sketch.

Shown in the figure below is single slit experiment. Monochromatic light of wavelength A, = 6.7e-07 meters comes in from the left and passes through the slit. The result is a pattern of bright and dark bands visible on a screen at a distance D = 3.58 meters away from the slit. The distance between the central maximum and the first dark fringe is y, = 0.0442 meters. Single Screen Slit dark dark D Determine the width of the slit. a = meters If the light is changed to a different color Ànew 4.75e-07 meters, the diffraction pattern changes. What is the new location of the first dark band? ynew = meters WARNING: The drawing is not to scale.

Calculate the width the interference fringe in the middle of the screen between two slits given the wavelength of the incident light is 444 nm and the distance between the slits is 0.013 mm. Take the distance between the slits and the screed D=1 m. Provide your answer in millimetres (mm).