wormgerar helcal 18.45 mm sheft leugh at 7 15 13.85 mm 4,5,6;7 spurglar от Skafeteught of 5 and 6 is - rongeurnal and axial force to year 5, 6, 7? given implent power = 11 W отрит power = 0.53 W ourpur speed = 8.9 rev/min number of Death: M = 0.0005 N₂=1 №₂ Na N ₁ = 28 16 = 10 N₂=45 moke Assumption if not enough informatius Find force applied 24 81= ك

View Sign Window Help yslfHVloOZkkOfyta7L.r8qTi9WCDPXVuo.pdf-Adi ne Tools Fundamentals of M... ACFrOgAWm2A-0.. x ☆ 日 @ 32 / 36 瓦,日 110% - The braket shown in fiqure is Subjected to three forces and one couple as Shown in fiqure. Find the result ant Rof the force System and the points of intersedion of it's line of action with the lines AB and BC. 37 N.m 120N 600N 30 200 mm 50 mm Y1OON Ame R = 446.86 N. O =26-58 O Type here to search loomm

(a) Water at 10°C (p = 999.7kg/m³ and u = 1.315 x 10-³Pa.s) is flowing steadily in a 0.10-cm diameter, 15-m-long stainless steel pipe at an average velocity of 2.4 m/s. Determine (i) the pressure drop, (ii) the head loss, and (iii) the pumping power requirement to overcome this pressure drop. (b) If the average water velocity is increased to 5.8 m/s in the same pipe then compare the pumping power requirement. (c) For the same useful pumping power input in part (a), determine the percent increase of the flow rate if the pipe is inclined 20° downward. Notel: The pump is located outside this pipe section. Note2: In case of turbulent flow, use the Moody Chart to obtain the friction factor and highlight the selected curves to obtain f value.