words is = 2.5. Now a manuscript with six new sonnets has come to light, and scholars are debating whether it is the poet's work. The new sonnets contain an average of = 10.2 words not used in the poet's known works. We expect poems by another author to contain more new words, so to see if we have evidence that the new sonnets are not by our poet we test Ho: μ = 8.9 Ha: μ > 8.9 Give the z test statistic and its P-value. What do you conclude about the authorship of the new poems?

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words is = 2.5. Now a manuscript with six new sonnets
has come to light, and scholars are debating whether it
is the poet's work. The new sonnets contain an average
of = 10.2 words not used in the poet's known works.
We expect poems by another author to contain more new
words, so to see if we have evidence that the new sonnets
are not by our poet we test
Ho: μ = 8.9
Ha: μ > 8.9
Give the z test statistic and its P-value. What do you
conclude about the authorship of the new poems?
Transcribed Image Text:words is = 2.5. Now a manuscript with six new sonnets has come to light, and scholars are debating whether it is the poet's work. The new sonnets contain an average of = 10.2 words not used in the poet's known works. We expect poems by another author to contain more new words, so to see if we have evidence that the new sonnets are not by our poet we test Ho: μ = 8.9 Ha: μ > 8.9 Give the z test statistic and its P-value. What do you conclude about the authorship of the new poems?
6.72 Who is the author? Statistics can help decide
the authorship of literary works. Sonnets by a certain
of
Elizabethan poet are known to contain an average
μ = 8.9 new words (words not used in the poet's other
works). The standard deviation of the number of new
н
Transcribed Image Text:6.72 Who is the author? Statistics can help decide the authorship of literary works. Sonnets by a certain of Elizabethan poet are known to contain an average μ = 8.9 new words (words not used in the poet's other works). The standard deviation of the number of new н
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