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two heterozygous black pigs are mated. show the genotypes,
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- Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?A cross between an orange-brown male and a homozygous black female produce four kittens. What is the phenotypic probability of the offspring? probability of the offspring?(This one is more complicated). Two true breeding fruit flies are allowed to mate. One fly ishomozygous dominant for body color and eye color while the other is homozygous recessive forbody color and eye color. (g+:gray body, g:black body, e+:ebony eyes, e:red), The F1 flies areallowed to mate. What are the following probabilities in the F2 generation? For this problemmake sure to show the Punnett Square for your F2 generation and all of your calculations. Youdo not need to show the Punnett Square for the F1 generation. Answer in percent and round to 2decimals.a. Two of three fruit flies are gray and red.b. The first fruit fly is gray and ebony, the second fruit fly is gray and red, and the third fruit fly is black and ebony.
- A red-eyed (dominant) female with a grey (dominant) body is crossed with red-eyed (dominant) male with a yellow body (recessive) The pair of fruit flies (given above) produce 320 offspring together from a single mating: 57 red-eyed females with grey bodies, 61 red-eyed females with yellow bodies, 22 brown- eyed females with grey bodies, 20 brown-eyed females with yellow bodies. 59 red-eyed males with grey bodies, 63 red-eyed males with yellow bodies, 20 brown-eyed males with grey bodies, 18 brown-eyed males with yellow bodies. From this information only (NO genetic diagrams required), what evidence and logic can you use to deduce the genetic identity of the parent flies?If a pure breeding(homozygous) black(dominant), longhaired (recessive) cat is made of pure breeding Siamese, shorthaired cat, and one of their male offspring has made it to one of their female offspring, what is the chance of producing a Siamese colored shorthair kitten?Two goats are mated together. One is tall and brown and of unknown genotype. The other is a short white goat. Assuming that tall (T) is dominant to short (t) and Brown (B) is dominant to white(b), what is the probability that they will produce a short, white offspring?
- The genetic identity of the female parent is RrGg and the genetic identity of the male parent is Rrgg. They produce 320 offspring together from a single mating: 57 red-eyed females with grey bodies, 61 red-eyed females with yellow bodies, 22 brown-eyed females with grey bodies, 20 brown-eyed females with yellow bodies.59 red-eyed males with grey bodies, 63 red-eyed males with yellow bodies, 20 brown-eyedmales with grey bodies, 18 brown-eyed males with yellow bodies. Show the simultaneous transmission of the two genes involved to give rise to the progeny given with the use of genetic diagrams and summaries as required. (Hint: you are only requiredto show the simultaneous transmission from the P to F1 generations)Imagine a cross between a man and a woman having the following genotypes: Genotype of the Husband Genotype of the Wife Aa bb Dd Gg Hh RR Tt X Aa Bb Dd gg Hh Rr Tt Assuming that the dominant allele in each gene pair exhibits complete dominance over the recessive allele, what is the probability that this couple would have a daughter who exhibits the recessive phenotype with respect to all seven of the gene pairs?Female pig Emmy Lou (straight tail, white-haired) with the haplotype cH/Ch was mated to a curly-tailed black-haired male pig Wilhelm (ch/ch). Curly tails are due to the cc genotype and black hair is due to the hh genotype. From the choices shown below, which genotype would you expect to be the most frequent among their offspring? cH/ch cH/ch CH/ch CH/ch ch/ch ch/ch cc/hh cc/hh All genotypes are equally likely. All genotypes are equally likely.
- Find the genotype of the missing parent. In Andalusian fowls, the black (B) and white (W) alleles are incompletely dominant In Andalusian fowls, black individudls (B) and white individuals (W) are homozygous. These alleles are incompletely dominant. Heterozygous fowls are bluish gray. A black bird is crossed with a bluish gray bird. What is the probability that the offspring are black? White? Bluish gray? В W BW ww W BW ww % white % black % bluish gray B. B.Draw a Punnet square indicating the F2 genotypes from the mating of an F1 male (QQBbHh) with an Fi female (QQBÜHH). Note: Make sure to write all the heterozygous genotypes as Gg, not gG.Hairlessness in dogs is inherited from a single dominant allele. Inheriting two dominant alleles is lethal for the embryo. Penelope, a hairless dog, is wildly attracted to a hairy dog, Arnold. They mate. The probability that Arnold's sperm fertilizing Penelope's oocyte results in a happy, hairless puppy is: O 1/2 O 3/4 O 1/3 Ο 1/4 O 2/3
