wo functions: y_1 = x^2 , y_2 = 1/x^2 are complementary solutions to the equation: x^2 y" + xy' - 4y = x^3 a.) Find the general solution   b.) Assume the bondary conditions: y(0) =0       y(3)=0.  What is y(2)?

Find y as a function of a if y" - 3y" - y' + 3y = 0, y(0) = -7, y' (0) = -4, y" (0) = 9. y(x) =

Is the equation t²y' (1) t + 4 - separable? y?

29, given in terms of x and y for an Implicit Equation of y2+ x2 = siny + 4 RMI 18) Find y'= A) 2y/(2x - sin y) C) - 2x/(2y - cos y) B) 2x/(2y - cos y) D) - 2y /(2x - sin y) 19) Find an equation of the tangent line y = mx + b to an Implicit Equation of y2+ x2 = siny + 4 at the point (2, 0). A) y = - 2x +4 B) y = 2 x- 4 C) y = - 4x + 6 D) y = 4x - 8 1.5 20) Find (e sin x) dx = by Using TI-Calculator. A) 0. 412 B) 0. 698 C) 1. 573 D) 2. 912 2

5.) Find by implicit differentiation dy dx a.) x+y = y² +2 b.) 4xel+yer=7 c.) ycos(x)=x^²+y2

the of the wing DE Show your complete solution & y = (3x' - e')(2y-5)

Solve using variation of parameters: y" + 5y' + 4y = 2e¬* 1. Find yc 2. Find u1 & u2 3. Find yp