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Transcribed Image Text:After conducting the signal speed experiment
a student has recorded the following data.
L₂ (m)
1.5
3
4.5
8
15
30
dt (ns)
6.50
13.72
21.02
38.10
72.20
145.42
L2 is the length of the longer cable in meters
and dt is the measured time delay in
nanoseconds. The student neglected to
record L₁, the length of the shorter cable.
After speaking with their instructor, they learn
all is not lost. They know the speed of the
signal can be calculated based on the distance
traveled divided by the time. However, the
recorded times measure how much longer the
signal had to travel in L2 compared to L₁. A
little bit of thought convinces them (correctly)
that
Transcribed Image Text:V =
L2-L1
dt
with v the signal speed. The student makes a
plot of dt (vertical axis) vs L₂ (horizontal axis)
and finds a signal speed. What speed do they
find in the units of meters per nanosecond?
Expert Solution
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Step 1
Given data:
| L2 (m) | dt(ns) |
| 1.5 | 6.50 |
| 3 | 13.72 |
| 4.5 | 21.02 |
| 8 | 38.10 |
| 15 | 72.20 |
| 30 | 145.42 |
To solve this probem, we need to consider the previous one as L1 for the next one.
For example, for L2=3 m, L1 will be 1.5 m and for L2= 4.5 m, L1 will be 3 m and so on. We need to find the corresponding dt accordingly. In the end, we need to find the average.
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