Assuming a reverse curve with the following parameters: Tangent @ Curve 1 = 40m Deflection Angle from PC to PRC = 60 degrees Stationing of the PC: 0+000 Tangent @Curve 1 = 50m Deflection Angle from PRC to PT = 50 degrees Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of points in the curve at 10m interval.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Assuming a reverse curve with the following parameters:
Tangent @ Curve 1 = 40m
Deflection Angle from PC to PRC = 60 degrees
Stationing of the PC: 0+000
Tangent @Curve 1 = 50m
Deflection Angle from PRC to PT = 50 degrees
Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of
points in the curve at 10m interval.
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Transcribed Image Text:Assuming a reverse curve with the following parameters: Tangent @ Curve 1 = 40m Deflection Angle from PC to PRC = 60 degrees Stationing of the PC: 0+000 Tangent @Curve 1 = 50m Deflection Angle from PRC to PT = 50 degrees Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of points in the curve at 10m interval. Use the editor to format your answer
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With the same problem, solve using this formulas. Draw the curve accurately.

Additional Problem: L(Curve Length) = R x I (angle of intersection) x pi/180

Degree of Arc basis
Chord Basis
R
R=
1145.916
D
10
sin
Transcribed Image Text:Degree of Arc basis Chord Basis R R= 1145.916 D 10 sin
Tangent Distance
Middle Ordinate
External Distance
Long Chord
T = R tan (2)
M = R(1-cos(
(→))
E = R(sec() - 1)
Lc = 2R sin /
2
Transcribed Image Text:Tangent Distance Middle Ordinate External Distance Long Chord T = R tan (2) M = R(1-cos( (→)) E = R(sec() - 1) Lc = 2R sin / 2
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