18 kg rifle bullet traveling 180 m/s buries itself in a 3.6 kg wooden block on 2.8 m long string making a pendulum. Neglect air resistance. Gravity is 9.8 m/s2. with the same collision, after the pendulum swings back to its original position (e- 0), it is struckby a second rifle bullet, also with mass m 18 g. traveling with the same speed ty as the first bullet After thesecond bullet has buried itself into the wood, what is the speed of the wood block, now with 2 bullets stuck in it?(A) 0.00 m/s(B) 0 11 m/s(C) 0.18 m/s(D) 0 21 m/s(E) 0.32 m/s(F) 0.64 m/s(G) 0.70 m/s(H) 0.90 m/s

By conservation of momentam mv=(m+M)v1 where m=mass of bullet M=mass of block

with the same collision, after the pendulum swings back to its original position (e-0), it is struck by a second rifie bullet, also with mass m-18 g. traveling with the same speed ny as the first bullet After the second bullet has buried itself into the wood, what is the speed of the wood block, now with 2 bullets stuck in it? (A) 0.00 m/s (B) 011 m/s (C) 0.18 m/s (D) 021 m/s (E) 0 32 m/s (F) 064 m/s (G) 0 70 m/s (H) 0 90 m/s

with the same collision, after the pendulum swings back to its original position (e-0), it is struck by a second rifie bullet, also with mass m-18 g. traveling with the same speed ny as the first bullet After the second bullet has buried itself into the wood, what is the speed of the wood block, now with 2 bullets stuck in it? (A) 0.00 m/s (B) 011 m/s (C) 0.18 m/s (D) 021 m/s (E) 0 32 m/s (F) 064 m/s (G) 0 70 m/s (H) 0 90 m/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Momentum And Collisions

Section: Chapter Questions

Problem 31P

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