With the assumption of no slipping, determine the mass m of the block which must be placed on the top of the cart (mc = 5.0 kg) in order that the system period be 0.58 s. What is the minimum coefficient of static friction for which the block will not slip relative to the cart if the cart is displaced 40 mm from the equilibrium position and released? Assume k = 740 N/m. -Hs m k m2 c

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (11) The angular velocity at the state 2?_ _(rad/s) (two decimal places) 111441 L₂ State 2 State 1

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (5) The stretched spring length of the spring at the state 2 is_ places) HULK ܪܐ TG नेता State 2 State 1 _(m) (two decimal

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