With the 360-lb cylindrical part P in its grip, the robotic arm pivots about O through the range -45° ≤ 0 ≤ 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 360-lb part P, the 100-lb weight of member OA (mass center at G₁), and the 60-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L2 are 2.8 ft and 2.0 ft, respectively. What is the maximum absolute value of Mo and at what value of 0 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. 42 lb-ft lb-ft lb-ft 0 2 G₁ 120° G B Questions: When 0= -26°, Mo= i When 0 = 6°, Mo= i When = 20°, Mo= i The maximum absolute value Momax = i lb-ft at 0= Mi

The wom an maint ains a slow steady motion over the indicated 135° range as she exercises her triceps muscle. For this condition, the tension in the cable can be assumed to be constant at W = 10 lb. Determine and plot the moment M of the cable tension as applied at A about the elbow joint O over the range 0<0< 135°. Find the maximum value of M and the value of 0 for which it occurs: Hint: you can use the computer to draw the graph M versus 0 and sketch it on your paper. B 21" 13" 45° W 24"-

With the 360-lb cylindrical part P in its grip, the robotic arm pivots about O through the range -45° ≤ 0 ≤ 45° with the angle at A locked at 120°. Determine and plot (as a function of 0) the moment at O due to the combined effects of the 360-lb part P, the 100-lb weight of member OA (mass center at G₁), and the 60-lb weight of member AB (mass center at G₂). The end grip is included as a part of member AB. The lengths L₁ and L₂ are 2.8 ft and 2.0 ft, respectively. What is the maximum absolute value of Mo and at what value of 0 does this maximum occur? The moment is positive if counterclockwise, negative if clockwise. After you have the plot, answer the questions. lb-ft lb-ft lb-ft 52 120⁰ G₂ G₁ T! L₂ L₂ B Mi Questions: When 0 = -26°, Mo= When 0 = 6°, Mo When 0 = 20°, Mo= i The maximum absolute value Momax = 1834.87 lb-ft at 0= 21.60

The motor lifts the 40-kg  crate with an acceleration of 6 m/s2 as shown in (Figure 1). Part A: Determine the x and y components of force reaction at the fixed support A using scalar notation. Express your answers in newtons to three significant figures separated by a comma.   Part B:  Determine the couple moment at the fixed support A. Express your answer in kilonewton meters to three significant figures. Enter positive value if the moment is counterclockwise and negative value if the moment is clockwise.