With Hash tables we have chaining and open addressing. What are the algorithms for both?how you would insert or search a hash table under either approach? Please give me examples of how I would code these algorithms

Does a hash table of size m consistently contain the same number of linked lists? I am unable to identify the purpose of a hash function, no matter how hard I attempt. To demonstrate your thesis, provide an example.

Is there a set limit on the number of linked lists that may be included in a hash table of size m? I've been trying to get my head around the purpose of a hash function, but I just can't seem to get it. Provide an example that helps to demonstrate how your theory is correct.

Is it consistent to say that a hash table of size m always contains the same number of linked lists? I've been trying to understand the purpose of a hash function for ages. Give an illustration of your point with an example.

Let us consider an empty hash table with 10 positions indexed from 0 to 9. Please illustrate the content of the hash table after inserting the elements 79, 8, 39, 48, 3, and 60 using(1) Quadratic Probing (2) Double hashing with h(k) = k%10 and h’(k)= 7-k%7

Using quadratic probing, what would be the answer for the following questions if you insert the following keys in sequence: 10, 17, 24, 31, 21, 19. (N = 7) While doing the insertions  keep track of the number of collisions for each key and get the final configuration of the structure.  Use the following quadratic hashing function: ((x mod 7) + j²) mod 7. What is the final configuration of the hash table? Use the indices from 0 to 6 to report where each key will be mapped. If the position has no value use the word empty. For example, if the final configuration is 10,17,24,31,21,19 (starting from index 0), your answer in the box should be 10,17,24,31,21,19,empty. Please don't use blank spaces or quotes to separate the values.          Report the number of collisions for each key using the order of insertion. For example, if you answer as 0,1,3,1,0,1, this means that you found 0 collisions for key 3, 1 collision for key 10, 3 collisions for key 17, 1 collision for key 24, 0 collisions…

Explain the collision resolution techniques used in hash tables when dealing with key collisions in dictionaries.

Can m-size linked lists be stored in a hash table? Why do we need to use a hash function, exactly? Give us a sample.

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Insert the following sequence of keys in the hash table.Keys = {4, 2, 1, 3, 5, 6, 8}Use linear probing technique for collision resolution: h(k, i) = [h(k) + i] mod mHash function, h(k) = 3k + 1Table size, M = 10 Draw the hash table, compute the index where the hashvalue will be inserted for each key, and show how you would use the technique when a collisionoccurs.