Wildlife biologists inspect 150 deer taken by hunters and find 30 of them carrying Lyme disease ticks. Formulas: For 94% confidence level z* =1.88, p(1-p) E = 2* . n a) The point estimate is p one decimal place. b) The standard error of the sample proportion is s.e. (p) = Write your answer to four decimal places. c) The margin of error with confidence level of 94% is E= Write your answer to four decimal Round to = places. d) We are 94% confident that the true population proportion of deer that carry Lyme disease ticks is

identify the t-score for a 90% confidence interval if the sample size is 31.        t=

Heights for teenage boys and girls were calculated. The mean height for the sample of 47 boys was 185 cm and the variance was 58. For the sample of 66 girls, the mean was 174 cm and the variance was 69. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 87% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. H

If n = 220, p-hat = 0.4, then what will be the 90% Confidence Interval for the population proportion?

Given this data: {4, 5, 8, 11, 16, 8},(a) Find the 90% confidence interval for the mean.(b) Interpret what does the interval mean?

A confidence interval for a population proportion p is 0.635 to 0.700. What is the margin of error?

n = 360 and p = 0.09, find the margin of error at a 99% confidence level

Find the critical value, for a 90% confidence when the sample size is 22

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

Identify the t-score for a 95% confidence interval if the sample size is 15. t =  the answer isnt 2.131 so what is the answer?