*7. Using superposition, find the voltage across the 6 A source in Fig. 125. = 24 V Rs 42 + V, - E, R R2 E, - 12 V 60 42 +8 V 1= 6A R3 30 2 R4120 FIG. 125 Problem 7. SECTION 3 Thévenin's Theorem "ork in 8. a. Find the Thévenin equivalent circuit for the network ex- ternal to the resistor R in Fig. 126. b. Find the current through R when R is 2 0, 30 2, and 100 Ω. Ry 4 2 E : R; 30 18 V Mohammed ali Ahmed

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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1::09
M24 N
FIG. 121
Problem 3.
ETWORK THEOREMS
ne 24 V
*7. Using superposition, find the voltage across the 6 A source
in Fig. 125.
R5
4Ω
+ V, -
E
R
R2
E,
- 12 V
+8 V
6Ω
40
I = 6A
R, 30 2 R, 120
FIG. 125
Problem 7.
SECTION 3 Thévenin's Theorem
work in
8. a. Find the Thévenin equivalent circuit for the networke
ternal to the resistor R in Fig. 126.
b. Find the current through R when R is 2 2, 30 N, and
100 Ω.
R
18 V
R2 30
Mohammed ali Ahmed
10:56e äc luI 21.03.04
FIG. 126
...
Transcribed Image Text:1::09 M24 N FIG. 121 Problem 3. ETWORK THEOREMS ne 24 V *7. Using superposition, find the voltage across the 6 A source in Fig. 125. R5 4Ω + V, - E R R2 E, - 12 V +8 V 6Ω 40 I = 6A R, 30 2 R, 120 FIG. 125 Problem 7. SECTION 3 Thévenin's Theorem work in 8. a. Find the Thévenin equivalent circuit for the networke ternal to the resistor R in Fig. 126. b. Find the current through R when R is 2 2, 30 N, and 100 Ω. R 18 V R2 30 Mohammed ali Ahmed 10:56e äc luI 21.03.04 FIG. 126 ...
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why the voltage all in negative,not should be positive?

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how to get this 10V?

12
Only -ovisactive.
GA.
M
H
12V
2A
+
41
m
+ v₁-
301
4
5
Ofe
C
G
T
+
41
n
127
31
VS=
VS-10 x 4
-
3.33V
4+5+3
Transcribed Image Text:12 Only -ovisactive. GA. M H 12V 2A + 41 m + v₁- 301 4 5 Ofe C G T + 41 n 127 31 VS= VS-10 x 4 - 3.33V 4+5+3
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