While in college student athletes can compete for four seasons in each sport. Due to the maturing of bodies and skill set, and more experience, it is often the case that the playing time of student athletes increases from their first year of participation until their fourth year of participation. Suppose population 1 is all female volleyball players in their fourth year of competition, and population 2 is all female volleyball players in their first year of competition. Of interest is to estimate the difference in the mean number of sets played by all female volleyball players in their fourth year of competition and the mean number of sets played by all female volleyball players in their first year of competition. A simple random sample of 8 female volleyball players in their fourth year of competition is selected, and the number of sets they played in their fourth year and the number of sets they played in their first year were recorded. The data is as follows. It is known that the population of differences in the number of sets played in the fourth and first years is normally distributed. If appropriate, use this information to test the hypotheses stated in question 8 at the a = .05 level of significance. Standard Deviation Student Fourth year First year Difference 2 1 61 54 23 51 38 3 3485 4 49 5 92 75 34 15 17 6 69 48 21 1255 7 72 17 8 96 84 12 Mean 72.00 47.50 24.50 17.24 23.34 16.90

Draw a Bell Curve We have given a data set- 220, 220, 250, 269, 275, 295, 305, 315, 320, 340, 362, 433, 449, 458 The mean and standard deviation of the data set is given as- Mean: 322.21428571429 Standard Deviation: 76.04057053585

11. Find the percentage from the standard normal tables for the following: [4 pt each] a) below z = 2.05 ____A______ (A) 97.98 (B) 99.38 (C) 2.02 (D) 47.48 b) between z = 0 and z = 3.00 _____D_____ (A) 99.87 (B) 50 (C) 149.87 (D) 49.87   c) above z = –1.00 _____B_____ (A) 34.52 (B) 84.13 (C)15.87 (D) none

1. The standard deviation of SAT scores is 100 points. A researcher decides to take a sample of 500 students’ scores to estimate the mean score of students in your state. What is the standard deviation of the sample mean? A) 0.2 B) 5 C) 4.47 D) 100 2. a binomial distribution with n = 10 and p = 0.2 . P(X = 5)= A) 0.34 B) 0.021 C) 0.026 D) 0.41