While an object is in projectile motion (with upward being positive) with no air resistance 1) the horizontal component of its velocity remains constant and the horizontal component of its acceleration is equal to -g. 2) the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g. 3) the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to zero. 4) the vertical component of both its velocity and its acceleration remain constant. 5) the vertical component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

While an object is in projectile motion (with upward being positive) with no air resistance 1) the horizontal component of its velocity remains constant and the horizontal component of its acceleration is equal to -g. 2) the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g. 3) the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to zero. 4) the vertical component of both its velocity and its acceleration remain constant. 5) the vertical component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Name: While an object is in projectile motion (with upward beingpositive) w
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: While an object is in projectile motion (with upward beingpositive) with no air resistance1) the horizontal component of its velocity remains constant and thehorizontal component of its acceleration is equal to -g.2) the horizontal component of its

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 57P: An aging coyote cannot run fast enough to catch a roadrunner. He purchases on eBay a set of...

See similar textbooks

Similar questions

An aging coyote cannot run fast enough to catch a roadrunner. He purchases on eBay a set of jet-powered roller skates, which provide a constant horizontal acceleration of 15.0 m/s2 (Fig. P3.57). The coyote starts at rest 70.0 m from the edge of a cliff at the instant the roadrunner zips past in the direction of the cliff. (a) Determine the minimum constant speed the roadrunner must have to reach the cliff before the coyote. At the edge of the cliff, the roadrunner escapes by making a sudden turn, while the coyote continues straight ahead. The coyotes skates remain horizontal and continue to operate while he is in flight, so his acceleration while in the air is (15.0i9.80j) m/s2. (b) The cliff is 100 m above the flat floor of the desert. Determine how far from the base of the vertical cliff the coyote lands. (c) Determine the components of the coyotes impact velocity.
A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider the motion from just after the moment it is launched to just before the moment it lands on the ground. When is the projectile’s acceleration equal to zero? a) Just after launch. b) Halfway to the highest point. c) Just before landing on the ground. d) At the highest point. e)The projectile's acceleration is never zero. f) The projectile's acceleration is always zero. At what point do the velocity and the acceleration have the same direction? a) Just after launch. b) Halfway to the highest point. c) Just before landing on the ground. d) At the highest point. e) The projectile’s velocity and acceleration always have the same direction. f) The projectile’s velocity and acceleration never have the same direction. At what point are the velocity and…
9) A projectile moves in a parabolic path without air resistance. a) Is there any point at which acceleration a is parallel to velocity v ? b) Is there any point at which acceleration a is perpendiculr tovelocity v ? Explain using a graph for full credit.
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay %3D Substituting ay = -g then simplifying results to t = sqrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( )( sqrt ( )) which is the expression for the horizontal distance at which you should drop the package.
Hunter kicks a soccer ball with an initial velocity of 25 m/s at 30o above the horizontal. Which of the following describes the horizontal component of the ball’s velocity? a It is zero b It is 25 m/s c It changes uniformly d It remains constant during the ball’s flight
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vịnitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t = sqrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( )( sqrt ( )) which is the expression for the horizontal distance at which you should drop the package.
3. The vector position ofa particle varies in time according to V the expression r = 3.00i – 6.00/j, where r is in meters and I is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (b) Determine the accelera- tion of the particle as a function of time. (c) Calculate the particle's position and velocity at = 1.00 s. 15
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t = sgrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dy = ( )( sqrt ( )) For Blank 8 which is the expression for the horizontal distance at which you should drop the package.
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay %3D Substituting ay=-g then simplifying results to t = sqrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt %3D Substituting the time taken by the package to reach to ground results to: ( sqrt ( which is the expression for the horizontal distance at which you should drop the package.
Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t= sqrt( which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = vxt Substituting the time taken by the package to reach to ground results to: dx = ( X sqrt ( which is the expression for the horizontal distance at which you should drop the package.
A player kicks a ball with an angle o 36° to the horizontal and initial velocity of 15.5 m/s. Assuming the ball is moving in the vertical plane, Calculate: a-) flight time or time the ball is in the air b-) speed when the ball reaches the ground
A stone was thrown with initial velocity of 20 m/s at angle 30 degrees above horizontal. If the stone is initially 35 m above the ground. Complete the sentences below. (0,0) 35 m 3 Vo=20.0 m/s 30.0°- 8. The impact velocity (just as it hit the ground) of the stone has y- component equal to heading downward 9. The horizontal displacement of the stone is 10. The stones impact velocity is ✿ the negative means that it is (x,- 35.0) : with an angle (standard angle) of • degrees.