College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- O West -1.36 x 10-3 J zero South A charge of 42.0 nC is placed in a uniform electric field that is directed towards the west direction and has a magnitude of 5.40 x 104 V/m. What work is done by the electric force when the charge moves a distance of 1.50 m in the direction 53° south of west? North -2.05 x 10-3 J 3.40 x 10-3 J Eastarrow_forwardplease helparrow_forwardA uniform electric field with magnitude of 8.00 * 104 that is directed vertically upward has a m charge of 40.0 nC placed inside. What is the change in potential energy of moving the charge a. 0.65 m to the right b. 0.85 m vertically upward C. 0.40 m downward at an angle of 25° from the horizontalarrow_forward
- Suppose an electron is released from rest in a uniform electric field whose magnitude is 6.30 x 10³ V/m. (a) Through what potential difference will it have passed after moving 1.00 cm? 2.21*10**-53 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V (b) How fast will the electron be moving after it has traveled 1.00 cm? m/sarrow_forwardAs a proton moves in the direction of an external electric fieldA) it is moving from low potential to high potential and the electrical energy of a system consisting of the proton and the electric field is increasing. B)it is moving from high potential to low potential and electrical energy of a system consisting of the proton and the electric field is increasing. C) it is moving from high potential to low potential and electrical potential energy of a system consisting of the proton and the electric field is decreasing. Dit is moving from low potential to high potential and electrical energy of a system consisting of the proton and the electric field is decreasing.arrow_forwardConsider a proton in a uniform electric field directed left to right, as shown in the figure. For both paths the initial speed of the proton is the same, but the direction of the initial velocity is different. Part (A) Compare the change in electric potential energy along path A to the change in electric potential energy along path B. ΔUA = ΔUB ΔUA > ΔUB There is not enough information given - we need either the initial speed or the size of the electric field. ΔUA < ΔUB Part (B) Compare the speed of the proton at the end of path A with the speed at the end of path B. vA = vB vA < vB It is impossible to tell - you need more information. vA > vBarrow_forward
- You and your colleagues have been tasked with launching a weather balloon into the Earth's stratosphere via rocket ship. In order to reduce fuel usage to meet with newly imposed fuel-consumption regulations, you are hoping to use the electric interaction between charges to your advantage. You have decided on the design below. You are able to place two Q = 1.98 C charges in the rocket ship and into the launching platform so that they are separated by a distance of yo = 2.93 m. You are allowed enough fuel to boost the rocket to an initial speed of vo = 309 m/s without accounting for the extra boost from the charges. The rocket on its own has a mass of 2.095x104 kg. The more equipment you can attach to your weather balloon (which is inside the rocket), the better. What limit do you put on the mass of the weather balloon and attached equipment? You may want to know the formula for gravitational potential energy for an object of mass m and height h: Egray = mgh, where g=9.81 m/s?. Edge of…arrow_forwardA charge of 28.0 nC is placed in a uniform electric field thatis directed vertically upward and has a magnitude of 4.00 * 10^4 V/m.What work is done by the electric force when the charge moves 0.670 m upwardarrow_forwardNear the surface of the Earth there is an electric. field of about 150 V/m which points downward. Two identical balls with mass m = 0.620 kg are dropped from a height of 2.30 m, but one of the balls is positively charged with q₁ = 950 μC, and the second is negatively charged with 92 = -950 μC. Part A Use conservation of energy to determine the difference in the speed of the two balls when they hit the ground. (Neglect air resistance.) Express your answer to three significant figures and include the appropriate units. V1 V2 = Submit Provide Feedback Value Request Answer Units ?arrow_forward
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