Which of the following performs a left outer join from the PAT_ENC_HSP table to the CLARITY_DEP table PAT_ENC_HSP.REFERRING_DEPT_ID has the same value as CLARITY_DEP.DEPARTMENT_ID? where A. FROM PAT_ENC_HSP peh, CLARITY DEP cd WHERE peh.REFERRING_DEPT_ID B. FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd WHERE peh.REFERRING DEPT_ID = cd.DEPARTMENT_ID = cd.DEPARTMENT_ID C. FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd ON peh. REFERRING DEPT_ID = cd.DEPARTMENT_ID D. FROM PAT_ENC_HSP.REFERRING DEPT ID LEFT OUTER JOIN CLARITY DEP. DEPARTMENT_ID

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Which of the following performs a left outer join from the PAT_ENC_HSP table to the CLARITY_DEP table where PAT_ENC_HSP.REFERRING_DEPT_ID has the same value as CLARITY_DEP.DEPARTMENT_ID?

A.  
```sql
FROM PAT_ENC_HSP peh, CLARITY_DEP cd WHERE peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID
```

B.  
```sql
FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd WHERE peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID
```

C.  
```sql
FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd ON peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID
```

D.  
```sql
FROM PAT_ENC_HSP.REFERRING_DEPT_ID LEFT OUTER JOIN CLARITY_DEP.DEPARTMENT_ID
```

**Explanation:**

Option C correctly uses the `LEFT OUTER JOIN` syntax with the `ON` clause to join `PAT_ENC_HSP` and `CLARITY_DEP` based on matching `REFERRING_DEPT_ID` and `DEPARTMENT_ID`.
Transcribed Image Text:Which of the following performs a left outer join from the PAT_ENC_HSP table to the CLARITY_DEP table where PAT_ENC_HSP.REFERRING_DEPT_ID has the same value as CLARITY_DEP.DEPARTMENT_ID? A. ```sql FROM PAT_ENC_HSP peh, CLARITY_DEP cd WHERE peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID ``` B. ```sql FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd WHERE peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID ``` C. ```sql FROM PAT_ENC_HSP peh LEFT OUTER JOIN CLARITY_DEP cd ON peh.REFERRING_DEPT_ID = cd.DEPARTMENT_ID ``` D. ```sql FROM PAT_ENC_HSP.REFERRING_DEPT_ID LEFT OUTER JOIN CLARITY_DEP.DEPARTMENT_ID ``` **Explanation:** Option C correctly uses the `LEFT OUTER JOIN` syntax with the `ON` clause to join `PAT_ENC_HSP` and `CLARITY_DEP` based on matching `REFERRING_DEPT_ID` and `DEPARTMENT_ID`.
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