Which of the following lines is perpendicular to the tangent line of y= х-3 at the point (2, –2) ? y = x - 8 5 O y = -3x + 4 -x - 4 y = 3 x + 4 y = 5 x - 8 y = 3

2. The slope of the tangent to a curve at any point (x, y) on the curve is O x+y=-1 O x² + y² = 5 O x² + y² = 25 O x² - y² = -7 Find the equation of the curve if the point (3, -4) is on the curve.

An equation of the line tangent to the graph of x) = x(1-2x)³ at the point (1,-1) is: y = - 7x+6 y = - 6x + 5 y = - 2x + 1 y = 7x- 8