Which of the following is the solution of the initial value problem ft²y" +4ty' +2y=0 \y(1) = 2, y'(1) = -1 โy(1) = y = 5t - 3 t² 1 У + t2 3 3 y=t+t2 y = 3 t−² — t−1 - y = 3 t¹t-2 Let y(x) be the solution of the initial value problem y' = У 1 + 1/4 + 5e-y/x, x Then y(2) 2 ln(k) with k equal to == Enter an integer value in the box provided. y(1)=0 Your Answer: Answer