College Physics
1st Edition
ISBN: 9781938168000
Author: Paul Peter Urone, Roger Hinrichs
Publisher: OpenStax College
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Transcribed Image Text:**Question:**
Which of the following is NOT a vector quantity?
- ○ force
- ○ impulse
- ○ all of the given quantities are vectors
- ○ displacement
- ○ momentum
- ○ velocity
- ○ acceleration
![**Problem Statement:**
A hockey puck (mass = 200 grams) is gliding on perfectly smooth (frictionless) ice at 10 m/s to the West. What is the momentum of the puck?
**Options:**
- ○ zero, since it is not changing speed
- ○ 20 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2000 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 200 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
**Explanation:**
To calculate the momentum (\( p \)) of the puck, use the formula:
\[ p = m \times v \]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
First, convert the mass from grams to kilograms:
\[ 200 \text{ g} = 0.2 \text{ kg} \]
Then, plug the values into the formula:
\[ p = 0.2 \text{ kg} \times 10 \text{ m/s} = 2 \text{ kg} \cdot \frac{\text{m}}{\text{s}} \]
Therefore, the correct answer is:
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West](https://content.bartleby.com/qna-images/question/e815d996-ac78-4584-a71e-4284151c4e48/02b853de-cce9-42c1-a093-77d27ad058f9/3xobs1r_processed.jpeg)
Transcribed Image Text:**Problem Statement:**
A hockey puck (mass = 200 grams) is gliding on perfectly smooth (frictionless) ice at 10 m/s to the West. What is the momentum of the puck?
**Options:**
- ○ zero, since it is not changing speed
- ○ 20 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2000 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 200 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
**Explanation:**
To calculate the momentum (\( p \)) of the puck, use the formula:
\[ p = m \times v \]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
First, convert the mass from grams to kilograms:
\[ 200 \text{ g} = 0.2 \text{ kg} \]
Then, plug the values into the formula:
\[ p = 0.2 \text{ kg} \times 10 \text{ m/s} = 2 \text{ kg} \cdot \frac{\text{m}}{\text{s}} \]
Therefore, the correct answer is:
- ○ 2 \((\text{kg} \cdot \frac{\text{m}}{\text{s}})\) West
Expert Solution
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Step 1
Given
Part-1: physical quantities is mentioned in a option
We have to choose the which quantity or quantities not a vector quantities
Part-2:
Mass of hockey puck = 200 g = 0.200 kg
Velocity of hockey puck = 10 m/s towards west
We have to calculate momentum of the hockey puck
Step by stepSolved in 2 steps
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