Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- For each statement below, decide whether it is true or false. If it is true, prove it. If it is not true, give a counterexample. All parts refer to languages over the alphabet {a, b}. (d) If neither L1 nor L2 can be accepted by an FA, then Lin L2 cannot.arrow_forwardThe next 3 questions pertain to the following grammar from the book. The string to test is aba. S→ XY X→ XA | a | b Y→AY|a A→ a Question 1 Enter which variables can generate the following substrings of length 2 as found in stage 2 of the CYK algorithm. Enter no spaces. Enter multiple variables separated by a comma in alphabetical order (e.g., XY). If there are no variables that generate the substring, enter none. ab e ba e Question 2 Enter which variables can generate the following substrings of length 3 as found in stage 3 of the CYK algorithm. Enter no spaces. Enter multiple variables separated by a comma in alphabetical order (e.g., X,Y). If there are no variables that generate the substring, enter none. a ba e ab a +arrow_forwardFor each statement below, decide whether it is true or false. If it is true, prove it. Ifit is not true, give a counterexample. All parts refer to languages over the alphabet {a, b}. (b) If Li C L2, and L2 cannot be accepted by an FA, then Li cannot.arrow_forward
- b) Write the CFG for the following language over alphabet Σ= {p,q ,r} L={ pqr, ppqrr, pppqrrr, ppppqrrrr, pppppqrrrrr, ……………..} Hint : pn q rn where n>=1 Note: derive at least four strings for the given CFGarrow_forwardWhich of the following best describes the set of strings that are Boolean expressions (e.g., "not p or (q and r)"), with the precedence rules 'not' > ‘and' > ‘or' for the three logical operators, left-associativity is supported, and sub- expressions in parentheses are also allowed? A. {S→E, E→T|E or T, T→FIT and F, F→ G | not G, G → (E) I plq|r} B. { S→ E, E →TIE and T, T→ FIT or F, F→ G | not G, G → (E) I plq|r} C. {S → El not E, E → TIE and T, T→FIT or F, F→ (E) I plq|r} D. {S → El not E, E→TI E or T, T→FIT and F, F→ (E) Ip|q|r}arrow_forwardBuild a TM to accept the language of all words of a's and b's that contain at least one aa or one bb. For example, ababba, bababaa, bababaabb are accepted, but ababab and bababab are not accepted.arrow_forward
- For each statement below, decide whether it is true or false. If it is true, prove it. If it is not true, give a counterexample. |All parts refer to languages over the alphabet {a, b}. (c) If neither Lı nor L2 can be accepted by an FA, then L1U L2 cannot.arrow_forwardBeginning Logic by E.J. Lemmon 1.5.1 J) -P →Q ⊦ -P v Q The rules we learned so far MTT DN CP &I &E vI vE RAA DF BICONDTIONAL Please list out all steps, including line numbers and where each rule derived fromarrow_forwardDiscrete Structures Section 1.2 Exercise Q9 and Q11. Show that each of the following conditional statements is a tautology using truth tables and without using truth tables.arrow_forward
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