Which of the following correctly ranks the electric potential energy U of the particle-field system at the labeled points? A UA=UB=Uc =Up в (UB = Uc = Up) > UA c) UA > UB >Uc >Up D Up > Uc > UB >UA

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A: Work done w = q (VB - VA )

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A: solution as

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A: Answer:   As per the given data,

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A: Using Coulomb's law of electrostatic force we can solve the problem as solved below

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Q: Figure 3.0 cm -2.0 nC 1.0 nC 3.0 cm 3.0 cm < 1 of 1 -2.0 nC Part A What is the electric potential…

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Q: Two 1.1 kg masses are 1.4 m apart (center to center) on a frictionless table. Each has +9.5 μC of…

A: given,masses:m1=1.1 kgm2=1.1 kgdistance between them:d=1.4 mcharge on each body:q1=9.5μc q2=9.5 μc

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A: 4b) The expression to find the (gravitational) weight is W=mg=0.1 g10-3 kg1 g9.8 ms2=9.8×10-4 N

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A: Given, V0=1.9×106 m/s L=2 cm==0.02 m d=1 cm=0.01m

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Q: Part A Two stationary positive point charges, charge 1 of magnitude 3.05 nC and charge 2 of…

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Q: Four point charges are placed in the xy coordinate system as shown figure. q1=q3=3.00 nC and q2=q4=…

A: q1 = 3 nC q2 = -3 nC q3 = 3 nC q4 = -3 nC distance of each charge from origin (r) = 9.2 cm = 0.092 m…

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A: Given: Diameter of glass sphere is 1.5 cm Changed to 9 nC

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A: Electric field strength = 100 NCDirection of electric field = downwards

Q: C 16-₂ . B X Decide whether each statement is true or false concerning the uniform electric field…

A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

Q: Choose the correct statement below about the uniform electric field shown below. O The kinetic…

A: This problem is from Electrostatics (Electrodynamics). We can clearly see that the electric field…

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Q: • Part A Two positive point charges are 5.00 cm apart. If the electric potential energy is 75.0 µJ,…

A: Given Displacement r                    = 5.0 cm = 0.05 m Electric potential energy U = 75.0 μJ =…

Q: A water molecule perpendicular to an electric field has 8.00x10-22 J more potential energy than a…

A: Solution:-Given thatFinal potential energy (90° to electric field)=8×10-22 J+Initial potential…