College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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which of the following choices cannot be a unit of electrical potential energy
n*m
Joule
Volt
eV
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- A cardiac defibrilator is used to shock a heart that is beating erratically. A capacitor in this device is charged to (6.14x10^3) V and stores (2.1900x10^2) J of energy. What is its capacitance? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answerarrow_forward#87: The flash unit in a camera uses a special circuit to “step up” the 3.0 V from the batteries to 300 V, which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 ms, and the average power dissipated in the flashlamp is 105 W. What is the capacitance of the capacitor?arrow_forwardA coaxial cable used in a transmission line has an inner radius of 0.11 mm and an outer radius of 0.65 mm. Calculate the capacitance per meter for the cable. Assume that the space between the conductors is filled with a material with a dielectric constant of 3.0. Number Unitsarrow_forward
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- Consider what happens when a person moves around in dry conditions. The rubbing of motion leads to static electric charge building up on the body. Assume the capacitance of the human body to be about 155 pF. a) How much charge would have to build up on a body to generate a potential difference of 10 kV? b) A particular cell phone can have its circuits destroyed if exposed to an electric shock containing 300 u.J of energy. What voltage does that correspond to if the shock is coming from a human body?arrow_forwardits not 39 volts it need to have a decimal like 12.1 or 13.1arrow_forwardA dielectric-filled parallel-plate capacitor has plate area AAA = 30.0 cm2cm2 , plate separation ddd = 10.0 mmmm and dielectric constant kkK = 3.00. The capacitor is connected to a battery that creates a constant voltage VVV = 5.00 VV . Throughout the problem, use ϵ0ϵ0epsilon_0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 . The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2U2U_2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3U3U_3.In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work WWW is done by the external agent acting on the dielectric?arrow_forward
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