Which of the following are true when considering the probability of spinning a multiple of 5 on an equal section spinner with numbers 1-20? which apply. a. P(A) = ⅕ b. n(S) = 20 c. n(A) = 4 d. n(A’) = 16 e. P(A) = 20% f. A = {5,10,15,20} g. P(A) = 4/20 h. P(A’) = ⅘ i. P(A’) = 0.8

The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 11 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 0.03. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 0.1. Fill in the tree diagram and... Answer as a decimal to 4 decimal places. D = event that someone actually has Zika %3D positive = event that a test states that a person has Zika Conditional Marginal Probabilities Joint Probabilities Probabilities 0.9700 Enter an integer or decimal number [more..] P(D and positive) P(positive | D) False 0.1100 0.0300 negative P(D) P(negative | D) P(D and negative) 0.1000 False Positive 0.8900 P(no D) P(positive | no D) P(no D and positive) 0.9000 P(negative | no D) P(no D and negative)

this helps... but the question is asking what is the expected times we would flip a head. My thinking is that we use the same approach as above but replace the [1..9] with 0 for (1/2)^10 and 1 for (1/2) .. (1/2)^9. I'm also not sure how to handle if the 10th flip is a head? Thanks!

Only need D E F

The length of life, in hours, of a drill bit in a mechanical operation has a Weibull distribution with a = 3 and ẞ= 60. Find the probability that the bit will fail before 12 hours of usage. The probability is ☐ (Round to four decimal places as needed.)