**QUESTION 1**Which hydrogen is removed by base in this elimination reaction?The diagram shows a molecular structure on the left, transitioning to a different structure on the right. On the left:- A carbon chain is depicted with two main carbon atoms, one of which is bonded to a bromine atom (Br). - Various hydrogens are labeled: Ha, Hb, Hc, and Hd, indicating their positions on different carbon atoms. The Ha hydrogens are at one terminal position, Hb is adjacent to the bromine, Hc is at the same carbon as the bromine, and Hd is on the subsequent carbon.On the right:- The structure shows a double bond formed between carbon atoms, indicating an elimination reaction has occurred, removing Br and one hydrogen.Options for selection:- ⭘ Ha- ⭘ Hb- ⭘ Hc- ⭘ Hd **Question 2**The reaction of t-butyl bromide, (CH₃)₃CBr, with methoxide, ⁻OCH₃, in methanol yields 2-methylpropene in an E2 reaction. What is the effect on the rate of reaction of doubling the concentration of t-butyl bromide?- ○ The rate is doubled.- ○ The rate is halved.- ○ The rate increases by four times.- ○ The rate stays the same.

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Step 1: Basic discussion

We know that E2 elimination basically means bimolecular elimination reaction. It happens in one step. The rate of such a reaction depends upon the concentration of the substrate as well as the concentration of the base.

$bold Rate bold space bold equals bold space bold K bold space bold left square bracket bold Substrate bold right square bracket bold space bold left square bracket bold Base bold right square bracket bold space$

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