Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question
**Oxidation Half-Reaction Identification** **Question:** Which half-reaction correctly represents oxidation? **Options:** A. \( \text{Fe}_{(s)} \rightarrow \text{Fe}^{+2}_{(aq)} + 2e^- \) B. \( \text{Fe}^{+2}_{(aq)} \rightarrow \text{Fe}_{(s)} + 2e^- \) C. \( \text{Fe}_{(s)} + 2e^- \rightarrow \text{Fe}^{+2}_{(aq)} \) D. \( \text{Fe}^{+2}_{(aq)} + 2e^- \rightarrow \text{Fe}_{(s)} \) **Explanation:** Oxidation is a process in which an element loses electrons. This can be represented in a half-reaction where the reactant gives up electrons to form a product. Here are the provided options along with their corresponding reactions: - **Option A:** \( \text{Fe}_{(s)} \rightarrow \text{Fe}^{+2}_{(aq)} + 2e^- \) This reaction shows that solid iron (Fe) loses two electrons to form a ferrous ion (\( \text{Fe}^{+2} \)) in aqueous solution. This is an example of an oxidation reaction since iron loses electrons. - **Option B:** \( \text{Fe}^{+2}_{(aq)} \rightarrow \text{Fe}_{(s)} + 2e^- \) This reaction shows a ferrous ion (\( \text{Fe}^{+2} \)) in aqueous solution losing electrons to form solid iron (Fe). This represents reduction, where the iron ion gains electrons to revert to its metallic form. - **Option C:** \( \text{Fe}_{(s)} + 2e^- \rightarrow \text{Fe}^{+2}_{(aq)} \) This reaction incorrectly places electrons on the reactant side for an oxidation process, which is not possible since electrons are lost (not gained) during oxidation. - **Option D:** \( \text{Fe}^{+2}_{(aq)} + 2e^- \rightarrow \text{Fe}_{(s)} \) This reaction shows a reduction process where a ferrous ion (\( \text{Fe}^{+2} \))
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Transcribed Image Text:**Oxidation Half-Reaction Identification** **Question:** Which half-reaction correctly represents oxidation? **Options:** A. \( \text{Fe}_{(s)} \rightarrow \text{Fe}^{+2}_{(aq)} + 2e^- \) B. \( \text{Fe}^{+2}_{(aq)} \rightarrow \text{Fe}_{(s)} + 2e^- \) C. \( \text{Fe}_{(s)} + 2e^- \rightarrow \text{Fe}^{+2}_{(aq)} \) D. \( \text{Fe}^{+2}_{(aq)} + 2e^- \rightarrow \text{Fe}_{(s)} \) **Explanation:** Oxidation is a process in which an element loses electrons. This can be represented in a half-reaction where the reactant gives up electrons to form a product. Here are the provided options along with their corresponding reactions: - **Option A:** \( \text{Fe}_{(s)} \rightarrow \text{Fe}^{+2}_{(aq)} + 2e^- \) This reaction shows that solid iron (Fe) loses two electrons to form a ferrous ion (\( \text{Fe}^{+2} \)) in aqueous solution. This is an example of an oxidation reaction since iron loses electrons. - **Option B:** \( \text{Fe}^{+2}_{(aq)} \rightarrow \text{Fe}_{(s)} + 2e^- \) This reaction shows a ferrous ion (\( \text{Fe}^{+2} \)) in aqueous solution losing electrons to form solid iron (Fe). This represents reduction, where the iron ion gains electrons to revert to its metallic form. - **Option C:** \( \text{Fe}_{(s)} + 2e^- \rightarrow \text{Fe}^{+2}_{(aq)} \) This reaction incorrectly places electrons on the reactant side for an oxidation process, which is not possible since electrons are lost (not gained) during oxidation. - **Option D:** \( \text{Fe}^{+2}_{(aq)} + 2e^- \rightarrow \text{Fe}_{(s)} \) This reaction shows a reduction process where a ferrous ion (\( \text{Fe}^{+2} \))
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