Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN: 9781337614085
Author: Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher: Cengage,
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Question
### Solving for x in a Parallelogram #### Diagram Explanation: The diagram shows a parallelogram ABCD. The vertices are labeled A, B, C, and D. The lengths of the sides are given as follows: - \(BC = 15\) - \(CD = 21\) - \(AD = 2x + 1\) #### Question: Which equation will help you solve for x using the given information in the diagram? #### Answer Choices: - \( \circ \; 2x + 1 + 15 = 21\) - \( \circ \; 2x + 1 = 15 + 21\) - \( \circ \; 2x + 1 = 21\) - \( \circ \; 2x + 1 = 15\) ### Comprehension: To determine which equation is correct, we need to remember a property of parallelograms: opposite sides are equal. This means \(AD\) is equal to \(BC\) and \(AB\) is equal to \(CD\). In this case, since \(AD\) is given as \(2x + 1\) and \(BC\) is \(15\), we can use the equation: \[ 2x + 1 = 15 \] Hence, the correct answer is: - \( \circ \; 2x + 1 = 15 \)
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Transcribed Image Text:### Solving for x in a Parallelogram #### Diagram Explanation: The diagram shows a parallelogram ABCD. The vertices are labeled A, B, C, and D. The lengths of the sides are given as follows: - \(BC = 15\) - \(CD = 21\) - \(AD = 2x + 1\) #### Question: Which equation will help you solve for x using the given information in the diagram? #### Answer Choices: - \( \circ \; 2x + 1 + 15 = 21\) - \( \circ \; 2x + 1 = 15 + 21\) - \( \circ \; 2x + 1 = 21\) - \( \circ \; 2x + 1 = 15\) ### Comprehension: To determine which equation is correct, we need to remember a property of parallelograms: opposite sides are equal. This means \(AD\) is equal to \(BC\) and \(AB\) is equal to \(CD\). In this case, since \(AD\) is given as \(2x + 1\) and \(BC\) is \(15\), we can use the equation: \[ 2x + 1 = 15 \] Hence, the correct answer is: - \( \circ \; 2x + 1 = 15 \)
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