Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Question:**
Which equation has the same solution as \( x^2 + 16x - 11 = 4 \)?

**Options:**
1. \( (x - 8)^2 = -49 \)
2. \( (x + 8)^2 = -49 \)
3. \( (x + 8)^2 = 79 \)
4. \( (x - 8)^2 = 79 \)

**Solution:**
In order to find which equation has the same solution as \( x^2 + 16x - 11 = 4 \), we first need to find the simplified form of the equation and compare it to the options provided:

1. Start by simplifying \( x^2 + 16x - 11 = 4 \):
   \[ x^2 + 16x - 15 = 0 \]

2. To solve this, we complete the square:
   - Move the constant term to the right side:
     \[ x^2 + 16x = 15 \]
   - Add and subtract \((\frac{16}{2})^2 = 64\) to complete the square:
     \[ x^2 + 16x + 64 = 15 + 64 \]
     \[ (x + 8)^2 = 79 \]

The correct equation that has the same solution is:
\[ (x + 8)^2 = 79 \]

Thus, the correct option is:
3. \( (x + 8)^2 = 79 \)
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Transcribed Image Text:**Question:** Which equation has the same solution as \( x^2 + 16x - 11 = 4 \)? **Options:** 1. \( (x - 8)^2 = -49 \) 2. \( (x + 8)^2 = -49 \) 3. \( (x + 8)^2 = 79 \) 4. \( (x - 8)^2 = 79 \) **Solution:** In order to find which equation has the same solution as \( x^2 + 16x - 11 = 4 \), we first need to find the simplified form of the equation and compare it to the options provided: 1. Start by simplifying \( x^2 + 16x - 11 = 4 \): \[ x^2 + 16x - 15 = 0 \] 2. To solve this, we complete the square: - Move the constant term to the right side: \[ x^2 + 16x = 15 \] - Add and subtract \((\frac{16}{2})^2 = 64\) to complete the square: \[ x^2 + 16x + 64 = 15 + 64 \] \[ (x + 8)^2 = 79 \] The correct equation that has the same solution is: \[ (x + 8)^2 = 79 \] Thus, the correct option is: 3. \( (x + 8)^2 = 79 \)
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