Where V is the voltage in volts (symbol V), I is the current in amperes or amps (symbol A), and R is the resistance in ohms (symbol 2). So the following simple circuit shows a battery and a resistor R: R Hilt

The capacitor in the circuit shown below is initially uncharged. The switch is closed at t = 0 s. AVbattery = 30 V, C = 3.0 F, and R = 2.0 Q. What is the current in the circuit at t = 7.5 s, in Ampere? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. R HIH

Four capacitors are connected in a circuit as shown in Fig. 4. Find the charge on, and the voltage across each capacitor. C, C, V 0.40 µF 0.40 µF C. 12 V 0.20 µF 0.60 μF

Q1) Ohm's Law (in electricity) states that the current (I) is proportional to the applied voltage (V). The constant of proportionality is the resistance (R). The resulting equation is: V = IR. This equation is re-arranged to: I = (1/R) V. Since this is a linear equation, the plot between V (on the x-axis) and I (on the y-axis) should be a straight line, with the slope being 1/R. In an experiment, the following data has been obtained for current for different values of the voltage. Voltage 1 2 3 Current 0.8 2.5 2.9 4.2 5.6 a) Determine the equation for the best-fit line from this data, by using the method of least squares. Equation: Plot the data points, and the straight line representing the equation that you found in part b) 'a'. (Note: the best-fit line will not pass through all the data points) c) Use the slope of the line to find the resistance. Resistance: LO