where there are a; + 1 options for each exponent x; because 0 ≤ x ≤ ai, and so the number ofpositive integer divisors is(a₁ + 1)(a₂ + 1)... (am + 1).

Answered: Image /qna-images/answer/404bff22-8586-4d9b-8c5b-c4b98f081ff1.jpg

Answered: where there are a; + 1 options for each…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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where there are a; + 1 options for each exponent x; because 0 ≤ x ≤ a,, and so the number of positive integer divisors is (a₁ + 1)(a₂ + 1)... (am + 1).