MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Males and females were asked what they would do if they received a $100 bill in the mail that was addressed to their neighbor, but had been incorrectly delivered to them. Of the 70 males sampled, 55 said yes they would return it to their neighbor. Of the 130 females sampled, 120 said yes. We want to construct a 90% confidence interval estimate for the difference between the true proportion of males who say they would return the money to their neighbor and the true proportion of females who say they would return the money to their neighbor. Choose the best option for the result of constructing that interval. O -226 < p1 -p2 < +.003 O-226 < p1 -p2 <.-.048 O -243 < p1 -p2 < -.031arrow_forwardSuppose a 95% confidence interval for the difference in test scores between Class 1 and Class 2 (in that order) is the following: 9 +/− 2. These results were based on independent samples of size 100 from each class. Now suppose you switch the order of Class 1 and Class 2 in your analysis but keep the data labeled correctly in terms of which class they came from. Which of the following statements is false? A) You can't do it this way. You'll get negative numbers for the difference in the means and/or negative numbers for the standard error. B) You are confident that the average for Class 2 is 7 to 11 points lower than for Class 1. C) You are still confident that the classes have significantly different mean scores. D) Your 95% confidence interval will now be entirely negative: from −7 to −11.arrow_forwardIndependent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Given a 90% confidence interval for the difference between the true average GPAs (seniors - sophomores) of (-0.05, 0.78), what can you conclude? Question 8 options: 1) There is no significant difference between the true average GPA for seniors and sophomores. 2) We do not have enough information to make a conclusion. 3) We are 90% confident that the average GPA of seniors is less than the average GPA of sophomores. 4) We are 90% confident that the average GPA of seniors is greater than the average GPA of sophomores. 5) We are 90% confident that the difference between the two sample GPAs falls within the interval.arrow_forward
- Suppose a new treatment for a certain disease is given to a sample of 180 patients. The treatment was successful for 153of the patients. Assume that these patients are representative of the population of individuals who have this disease. Calculate a 98% confidence interval for the proportion successfully treated. (Round the answers to three decimal places.)arrow_forwardWhich of the following is the BEST interpretation of the 97% one-sample confidence interval? If we consider all possible 97% one-sample confidence intervals arising from all possible samples of places in Florida, then 97% of those intervals should contain the average rainfall amount for all places in Florida. If we consider all possible 97% one-sample confidence intervals arising from all possible samples of size 12, then all of those intervals should contain the average rainfall amount for all places in Florida. If we consider all possible 97% one-sample confidence intervals arising from all possible samples of size 12, then 97% of those intervals should contain the average rainfall amount for all places in Florida. If we consider all possible places in Florida, then 97% of those places should have the average rainfall amount for Florida. If we consider all possible one-sample confidence intervals arising from all possible…arrow_forwardA genetic experiment with peas resulted in one sample of offspring that consisted of 447 green peas and 169 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?arrow_forward
- you conducted additional studies with these men and found the following: a. The RR for those who drank one drink per day was 1.50 (95% CI:1.32-1.67) in comparison to the abstainers. b. For those men who drank three or more drinks per day the RR compared to the abstainers was 4.20 (95% CI 2.68-5.85). Question: We can tell from the Confidence Intervals provided in #7 whether there are likely more people in the “one drink a day” group or the “3+ drinks per day” group. Which one likely has more people and how can we tell?arrow_forwardA graduate Statistic Student wants to estimate the true proportion of county college ("c.c.") students in here state who go on to receive an Associate Degree (AD ), She is able to take a random sample of n = 100 of those c.c. stuents, and 64 of those students received an AD. Find her 90% confidence interval for the true proportion of c.c. students in her state that receive an AD. Be sure to either i)Use full calculator syntax including proper label on your output or i)write down the formula, plug in the appropriate nun bers, and then give the calculated interval including a proper label. 1-prop-Z Int x: 64,n: 100, Clevel.90, interval (.56105,.71895 b. 1-prop-Z Int x: 64,n: 100, Clevel .90, interval (.66105,.71896 1-prop-Z Int x: 64,n: 100, Clevel .90, interval (.51105,.70950 1-prop-Z Int x: 64,n: 100, Clevel .90, interval (.61105,.81105 by C.arrow_forwardA genetic experiment with peas resulted in one sample of offspring that consisted of 442 green peas and 156 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradictexpectations?arrow_forward
- A professor sampled 46 students from a large university to obtain a 95% confidence interval for the proportion of students in favor of raising ASB fees. The interval was (0.356, 0.397). If the professor had used a 90% confidence interval instead, the confidence interval would have been ... A) Wider and would have a smaller chance of missing the true proportion. B) Narrower and would have a larger chance of missing the true proportion. C) Narrower and would have a smaller chance of missing the true proportion. D) Wider and would have a larger chance of missing the true proportion.arrow_forwardA genetic experiment with peas resulted in one sample of offspring that consisted of 417green peas and166yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? A genetic experiment with peas resulted in one sample of offspring that consisted of 417 green peas and 166 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?arrow_forwardWhat if we're able to use a normal model. To construct a 95% Confidence Interval, we use the following formula: p hat ± ME for 95% CI If p hat = 0.38 and ME for 95% CI = 0.096, what is CI? Keep the numbers in 3 decimal places. Put the two numbers in ( ) and use a comma, then a space between the two numbers.arrow_forward
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