Please answer the question(s) with the same format given on the example. Thank you so much! When variance is unknown (if the population is finite with meanWhen variance is unknown (if the population is finite with meanu and standard deviation o or the sampling is withoutu and standard deviation o or the sampling is withoutreplacement)Example 1. Random samples with size 4 are drawn from apopulation having the values 14,19,26,20,44 and 47. Find themean and the standard error of the sample means.replacement)Example 2. Consider a group of N = 4 people with the followingages: 16,18, 20 and 22. Consider samples of size n = 2 from thegroup. Find the mean and variance of the sampling distribution.Solution:Solution:A. Solving the population mean:16+18+20+22_ 76A. Solving the population mean:14+19+26+20+44+47 _ 1706.= 28.33=1946B. Solving for sample mean:B. Solving for sample mean: * = 4X = u = 28.33I=μ= 19C. To compute for the population standard deviation:(16 – 19)* + (18 – 19)° +(20 – 19) +(22 – 19) _ 20C. To get the standard error of the sample means, computefirst the population standard deviation:(14- 28 33) + (19– 28.33)° + (26 – 28.33)* + (20 – 28. 33)° + (44 –- 28.33)° + (47 – 28.33F4D. Solving for variance of the sample:o N-n 5 4–2N-1 2 4-1205.35 + 87.05 + S.43 + 69 39 + 245.53 + 348.57961.33- JT0. 22 - 12.66of =:= 2.5.67 =1.6756=-..D. Solving for standard of error of the mean:N-n12.666-412.66= 3.165 ..6325 = 2.00N-146-14АСTIVITY:1. If a population consist of the values (3,5,8,9). Consider possible samples of size 2. Find the mean and variance ofthe sample mean.2. A population consists of three numbers (3,4,7). Consider all possible samples of size 2 which can be drawn fromthe population. Find the mean and variance of the sampling distribution of the sample means.3. A population consist of five numbers 6, 9, 12, 15, and 18. Find the mean and variance of the sample means whensample size is 3.

Since there are multiple questions, as per the honor code the first question will be solved. Dear…

When variance is unknown (if the population is finite with mean µ and standard deviation o or the sampling is without When variance is unknown (if the population is finite with mean u and standard deviation o or the sampling is without replacement) Example 1. Random samples with size 4 are drawn from a population having the values 14,19,26,20,44 and 47. Find the mean and the standard error of the sample means. replacement) Example 2. Consider a group of N = 4 people with the following ages: 16,18, 20 and 22. Consider samples of size n = 2 from the group. Find the mean and variance of the sampling distribution. Solution: Solution: A. Solving the population mean: A. Solving the population mean: 14+19+26+ 20+44+47 _ 170 16+18+20+22_ 76 =19 28.33 6 B. Solving for sample mean: x = µ = 28.33 B. Solving for sample mean: * = 4 x = µ = 19 C. To compute for the population standard deviation: (16 – 19)} + (18 – 19)* + (20 – 19) +(22 – 19) _ 20 C. To get the standard error of the sample means, compute first the population standard deviation: 14-28 33) - (19 - 28.33)* + (26 - 28.33)* + (20 - 28. 33) + (44 – 28.33)° + (47 –- 28.33 D. Solving for variance of the sample: o N-n 5 4-2 = =2.5•.67=1.675 N-1 2 4-1 205.35 87.05 5.43 + 69 39 + 245.55 + 348.5 - Te0. 22 - 12 66 of = D. Solving for standard of error of the mean: N-n 12.66 6-4 12.66 = 3.165..6325 =2.00 N-1 АCTIVITY: 1. Ifa population consist of the values (3,5,8,9). Consider possible samples of size 2. Find the mean and variance of the sample mean. 2. A population consists of three numbers (3,4,7). Consider all possible samples of size 2 which can be drawn from the population. Find the mean and variance of the sampling distribution of the sample means. 3. A population consist of five numbers 6, 9, 12, 15, and 18. Find the mean and variance of the sample means when sample size is 3.

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 19PFA