
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. This is equal to the product of the separate magnification values mm of each lens. In equation form
mtotal=(m1)(m2).
A 1.20 cm tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm . A second lens, this one having a focal length of magnitude 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis.
A)
Find the location and height of the image (call it I2) formed by the lens with a focal length of 40.0 cm if the first lens is diverging and the second lens is a converging.
B)
I2 is now the object for the second lens. Find the location and height of the image produced by the second lens.
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Please Asaparrow_forwardA concave spherical mirror has a radius of curvature, R = 18.2 cm. If an object is placed 53.4 cm in front of the lens, what is the magnification of the image produced?arrow_forwardA typical human eye is nearly spherical, and is usually about 2.5 cm in diameter. Suppose a person first looks at a coin that is 2.4 cm in diameter and located 34.0 cm from her eye. Then, she looks up at a friend who is 1.8 m tall and 4.00 m away. Find the magnitude of the approximate size of each image (coin ℎI,coin and friend ℎI,friend) on her retina. (Hint: Just consider rays from the top and bottom of the object that pass through the center of the lens.) b) Are the images on her retina upright/inverted and/or virtual/real?arrow_forward
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