When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. This is equal to the product of the separate magnification values mm of each lens. In equation form mtotal=(m1)(m2).   A 1.20 cm tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm . A second lens, this one having a focal length of magnitude 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. A)  Find the location and height of the image (call it I2) formed by the lens with a focal length of 40.0 cm if the first lens is diverging and the second lens is a converging.   B) I2 is now the object for the second lens. Find the location and height of the image produced by the second lens.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
Problem 63P
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When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. This is equal to the product of the separate magnification values mm of each lens. In equation form

mtotal=(m1)(m2).  

A 1.20 cm tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm . A second lens, this one having a focal length of magnitude 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis.

A) 

Find the location and height of the image (call it I2) formed by the lens with a focal length of 40.0 cm if the first lens is diverging and the second lens is a converging.
 
B)
I2 is now the object for the second lens. Find the location and height of the image produced by the second lens.
 

 

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