When the light of a wavelength λ = 561 nm is incident on a diffraction grating the first maximum after the center one is found to occur at an angle of θ1 = 7.5 degrees.  Part (a)  Write an expression for the grating's line density, n, in terms of the given quantities.  Part (b)  Calculate this spacing in lines per centimeter?   Part (c)  Find the angle of the second-order intensity maximum, θ2, in degrees.

Intense white light is incident on a diffraction grating that has 600. lines/mm. (a) What is the highest order in which the complete visible spectrum can be seen with this grating? (b) What is the angular separation between the violet edge (400. nm) and the red edge (700. nm) of the first - order spectrum produced by the grating?

The wavelengths of the visible spectrum are approximately 400nm (violet) to 700nm (red). Find the angular width of the first-order visible spectrum produced by a transmission diffraction grating with 433 lines per millimeter when white light falls normally on the grating.Give your answer in degrees.

For a certain diffraction grating, the ratio l/a of wavelength to ruling spacing is 1/3.5.Without written calculation or use of a calculator, determine which of the orders beyond the zeroth order appear in the diffraction pattern.

Light of wavelength 588.2 nm illuminates a slit of width 0.63 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.86 mm from the central maximum? (b) Calculate the width of the central maximum. Step 1 (a) As shown in the figure, dark bands or minima occur where sin 0 = m(2/a). For the first minimum, m = 1 and the distance from the center of the central maximum to the first minimum is y₁ = L tan 8, where L is the distance of the viewing screen from the slit. 32 sin dark = 22/a 31 sin dark = λ/a HE 0 -1 sin dark = -λ/a -2 sin dark = -22/a Viewing screen a Because is very small, we can use the approximation tan sin 0 = m(2/a). Substituting the approximation and solving for the distance to the screen, we have 6.3 x 10 m ³ m ) (₁ L = = y ₁ ( ² ) = x 10-3 m x 10-⁹ m m.

The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating having 870  lines/mm, over what range of angles does the visible m  = 1 spectrum extend?Express your answers in degrees separated by a comma.

A thin sheet of transparent material has an index of refraction of 1.40 and is 15.0 µm thick. When it is inserted in the light path along one arm of an interferometer, how many fringe shifts occur in the pattern? Assume the wavelength (in a vac- uum) of the light used is 600 nm. Hint: The wavelength will change within the material.

The wavelengths of the visible spectrum are approximately 400nm (violet) to 700nm (red). Find the angular width of the first-order visible spectrum produced by a transmission diffraction grating with 433 lines per millimeter when white light falls normally on the grating.Give your answer in degrees.

A transmission grating with d=1.5μm is illuminated at various angles of incidence by light of wavelength 600nm. Derive an expression for the angular deviation of the first order diffracted beam (m=1) compared to the 0th order (m=0) as a function of the angle of incidence. Plot as a function of angle of incidence (0 to 90 degrees) the angular deviation of the first order diffracted beam from the 0th order (m=0) beam.

A laser beam is normally incident on a diffraction grating. The wavelength of the incident light is 1 = 560 nm, and the third-order maximum of the diffraction pattern is measured to be at an angle of 32.0°. (a) What is the density of rulings for the grating (in grooves/cm)? grooves/cm (b) Determine the total number of primary maxima that can be observed in this situation. primary maxima Need Help? Read It