When the 0.08-kg body is in the position shown, the linear spring is stretched 8 mm. Determine the force P required to brea at C. Complete solutions for (a) including the effects of the weight and (b) neglecting the weight. P 64 mm 64 mm k = 1550 N/m B 36 mm 36 mm

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When the 0.08-kg body is in the position shown, the linear spring is stretched 8 mm. Determine the force P required to break contact
at C. Complete solutions for (a) including the effects of the weight and (b) neglecting the weight.
64 mm 64 mm-
k = 1550 N/m
B
36 mm
36 mm
Transcribed Image Text:When the 0.08-kg body is in the position shown, the linear spring is stretched 8 mm. Determine the force P required to break contact at C. Complete solutions for (a) including the effects of the weight and (b) neglecting the weight. 64 mm 64 mm- k = 1550 N/m B 36 mm 36 mm
Expert Solution
Step 1

Given: The mass of the body is 0.08 kg. 

           The spring is stretched to 8 mm. 

           The spring constant is 1550 N/m 

To determine: (a) The force P when weight is included 

Note: 1 mm is equal to 0.001 m, so 8 mm is equal to 0.008 m. 

The formula for spring force is 

F=kx

where k is the spring constant and x is the stretch on spring 

Substitute the values 

F=1550 N/m×0.008 mF=12.4 N

The moment is equal to the product of force and perpendicular distance to the pivot point. 

The anticlockwise direction is taken as positive and clockwise direction is taken as negative. 

 

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