Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Mendel testcrossed pea plants grown from yellow, round F1 seeds to plants grown from green, wrinkled seeds and obtained the following results: 31 yellow, round; 26 green, round; 27 yellow, wrinkled; and 26 green, wrinkled. Are these results consistent with the hypothesis that seed color and seed texture are controlled by independently assorting genes, each segregating two alleles?arrow_forwardPerform two consecutive crosses similar to those of Mendel for the following individual plants. Plants with round seeds (RR) are crossing with plants with wrinkled seeds (rr). After the first cross, cross the offspring together to generate F2 offspring. What are the genotypic and phenotypic ration of F2?arrow_forward))((())&&&@@@arrow_forward
- Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forward23. What is the probability that the progeny of a cross between two individuals that are AABBCCDD will have the same genotype as the parents? A) 1/256 B) 1/16 C) 1/4 D) 1 24. Which of the following inheritance patterns describes the ability of a single allele to have multiple phenotypic effects? A) incomplete dominance B) multiple alleles C) pleiotropy D) epistasis 25. Phenylketonuria (PKU) is an inherited disease caused by a recessive autosomal allele. If two individuals are both carriers, what is the probability that their first child will be a carrier for PKU? A) 1/4 В) 1/2 С) 3/16 D) 3/8arrow_forwardDr. Thompson learned in her university genetics course to memorize probability outcomes from monohybrid crossing scenarios so there is never a need for drawing Punnett squares or forked line diagrams. Which equation would Dr. Thompson use to predict the probability of obtaining a tester outcome from the cross of MmNn X Mmnn? a) ¼ mm X ½ nn. b) ½ mm X ½ nn. c) ½ Mm X ½ nn. d) ½ Mm X ¼ nn.arrow_forward
- A white-flowered plant is crossed with a red-flowered plant and all of the offspring are pink. This is an example of: A) sex-linked inheritance B) the principle of segregation C) incomplete dominance D) linked genes E) codominancearrow_forwardIn dogs, a dominant gene (H) produces wire-haired texture. The recessive allele (h) produces smooth hair. A heterozygous wire-haired male is mated to a female with smooth hair. a) Draw a punnet square and solve the cross. b) What genotypes and phenotypes are expected in the F1 generation, and in what ratios?arrow_forwardA pure strain of Mendel’s peas, dominant for all seven of his independently assorting genes, was testcrossed. (a) How many different kinds of gametes could each of the parents produce? (b) How many different gametes could the F1 produce? (c) If the F1, was testcrossed, how many phenotypes would be expected in the offspring and in what proportions? d) How many genotypes would be expected in the F2? (e) How many combinations of F1 gametes are theoretically possible (considering, e.g., AABBCCDDEEFFGG sperm nucleus x aabbccddeefigg egg nucleus a different combination than AABBCCDDEEFFGG egg nucleus x aabbccddeeflgg sperm nucleus)? (f) How many different kinds of matings could theoretically be made among the F2?arrow_forward
- In tomatoes, the red fruit color is completely dominant to yellow. Suppose a tomato plant homozygous for red is crossed with one homozygous for yellow and the progeny are allowed to self pollinate. What phenotypes do you predict in the F2 generation? a) 3 red: 1 yellow b) 9 red : 3 orange : 1 yellow c) 1 red : 2 orange : 1 yellow d) 1 red : 1 yellowarrow_forwardIn guinea pigs, black hair colour (B) is dominant and brown hair colour (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: (a) Find the gamete types for the cross: BbLl X BbLL (b) What are the phenotypes of the parent generation? (c) What are the genotypes and phenotypes of the F1 generation?arrow_forwardYou carry out a trihybrid cross (a cross in which the parental plants differ for three characters) between a tall pea plant with round, yellow seeds (TT RR YY) and a short pea plant with wrinkled, green seeds (tt rr yy). The parental plants are homozygous for all of the three characters. They are crossed to produce the F1 generation. Tall, round, and yellow are the dominant traits for each character. What will be the phenotypes of the F1 generation?arrow_forward
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