When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?Similarly, when do (object distance) is very small and less, what does the thin lens equation predict for the value of 1/f? Please explain your answer properly, especially for the first question. Thank you

When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?Similarly, when do (object distance) is very small and less, what does the thin lens equation predict for the value of 1/f? Please explain your answer properly, especially for the first question. Thank you

When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?Similarly, when do (object distance) is very small and less, what does the thin lens equation predict for the value of 1/f?
Please explain your answer properly, especially for the first question. Thank you

Expert Solution

Step 1

Introduction:

A lens is a portion of a transparent medium bounded by two spherical surfaces or one spherical surface and one plane surface.

Explanation:

Thin lens equation is given by,

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \to (1) W h e r e, v i s t h e i m a g e d i s \tan c e . u i s t h e o b j e c t d i s \tan c e . f i s t h e f o c a l l e n g t h o f t h e l e n s .$