When an aqueous solution of copper sulphate is electrolyzed, copper is deposited at the cathode (clue: get the reduction half equation from the table of standard reduction potentials). If a constant current was passed for 5 hours and 404 mg of Cu was deposited, calculate the current passed through CuSO₄. (Atomic mass of Cu is 63.55 amu). What is the number of faradays (F) of electricity required to liberate 134.4 L of hydrogen gas (H₂) from a solution containing H⁺ ions? (22.4 L of H₂ is equal to 1 mol of H₂) 2 H+ + 2 e- > H2 (g) References/Given Values: Faraday’s Constant: F = 96,485 C/mol eˉ; Atomic Mass of H = 1 amu
When an aqueous solution of copper sulphate is electrolyzed, copper is deposited at the cathode (clue: get the reduction half equation from the table of standard reduction potentials). If a constant current was passed for 5 hours and 404 mg of Cu was deposited, calculate the current passed through CuSO₄. (Atomic mass of Cu is 63.55 amu). What is the number of faradays (F) of electricity required to liberate 134.4 L of hydrogen gas (H₂) from a solution containing H⁺ ions? (22.4 L of H₂ is equal to 1 mol of H₂) 2 H+ + 2 e- > H2 (g) References/Given Values: Faraday’s Constant: F = 96,485 C/mol eˉ; Atomic Mass of H = 1 amu
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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When an aqueous solution of copper sulphate is electrolyzed, copper is deposited at the cathode (clue: get the reduction half equation from the table of standard reduction potentials). If a constant current was passed for 5 hours and 404 mg of Cu was deposited, calculate the current passed through CuSO₄. (
What is the number of faradays (F) of electricity required to liberate 134.4 L of hydrogen gas (H₂) from a solution containing H⁺ ions? (22.4 L of H₂ is equal to 1 mol of H₂) 2 H+ + 2 e- > H2 (g)
References/Given Values: Faraday’s Constant: F = 96,485 C/mol eˉ;
Atomic Mass of H = 1 amu
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