When a poultry farmer uses his regular feed, the newborn chickens have normally distributed weights with a mean of 61.4 oz. In an experiment with an enriched feed mixture, ten chickens are born with the following weights (in ounces). 65.7, 61.5, 67, 64.1, 67.7, 64.2, 67.1, 66.4, 65.3, 63.4 Use the a = 0.05 significance level to test the claim that the mean weight is higher with the enriched feed.
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- Suppose you are asked to toss a coin 16 times and calculate the proportion of the tosses that were heads. a. What shape would you expect this histogram to be and why? b. Where you do expect the histogram to be centered? c. How much variability would you expect among these proportions? d. Explain why a Normal model should not be used here.The accompanying data table lists the magnitudes of 50 earthquakes measured on the Richter scale. Test the claim that the population of earthquakes has a mean magnitude greater than 1.00. Use a 0.05 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and conclusion for the test. Assume this is a simple random sample. A. Identify the test statistic. t equals (Round to two decimal places as needed.) B. Identify the P-value. The P-value is (Round to three decimal places as needed.)Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 18 μg/g. Assume that the sample is a simple random sample. 12.5 11 10.5 21 11.5 17.5 8 12 8 18.5
- Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…A) What is the mean difference score, MD? (Hint: fill in the difference column using TMS - minus - Sham) a. 4 b. 5 c. 20 d. 4.2 B) What is the sample variance, s2, for the difference scores? a. 7.2 b. -9 c. 8.5 d. 9
- Listed below are the lead concentrations (in ug/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg /g. 2.96 6.45 5.99 5.51 20.53 7.45 11.97 20.46 11.52 17.54 D Identify the null and alternative hypotheses. Ho: H1: (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. V the null hypothesis. There sufficient evidence at the 0.01 significance level to V the claim that the mean lead concentration for all Ayurveda medicines…The average family size was reported as 7.2. A random sample of families in a particular school district resulted in the following family sizes: Size 4 9. 8. 4 8 9 At 1% level of significance, does the average family size different from the national average? Use traditional way of testing hypothesis. a. Mean family size of the sample: b. Sample variance: ct Test Value: d. Summarize your Interpretation: 4)Listed below are the lead concentrations (in µg/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg/g. 5.98 5.50 20.54 3.03 6.46 Identify the null and alternative hypotheses. Ho: H 14 H₁: μ 14 (Type integers or decimals. Do not round.) Identify the test statistic. = (Round to two decimal places as needed.) 7.45 12.01 20.47 11.48 17.53 D S Vi I. (1,0) More
- Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 21 μg/g. Assume that the sample is a simple random sample. 19.5 21 7.5 19 14 20 10 12 21.5 16.5For a repeated-measures ANOVA, n = 6, k = 3, and error SS= 40. Therefore, MSerror = _______. a. 4 b. 8 c. 6 d. 2.22(a) Using the information above, part of the ANOVA table is: Source of variation Sum of squares Region I error II Find the values of (round off to two decimal points) (1) I (11) II