When a 2-mm-diameter tube is inserted into a liquid in an open tank, the liquid is observed to rise 10 mm above the free surface of the liquid. The contact angle between the liquid and the tube is zero and the specific weight of the liquid is 1.2 X 104 N/m3. Determine the value of the surface tension for this liquid.

When a 2-mm-diameter tube is inserted into a liquid in an open tank, the liquid is observed to rise 10 mm above the free surface of the liquid. The contact angle between the liquid and the tube is zero, and the specific weight of the liquid is 1.2 × 104 N/m3. Determine the value of the surface tension for this liquid. Show step-by-step, and explain each step. Thank you.

1. A device for measuring the specific weight of a liquid consists of a U-tube manometer as shown. The manometer tube has an internal diameter of 0.5 cm and originally has water in it. Exactly 2 cm³ of unknown liquid is then poured into one leg of the manometer, and a displacement of 5 cm is measured between the surfaces as shown. What is the specific weight of the unknown liquid? Answer: Y = 0.5 cm. T 5 cm ↓ Water

Determine the height of the mercury in the tube if the level of water in the tube is h = 0.3m and the depths of the oil and water in the tank are 0.6 and 0.5 m, respectively as shown in Figure Q5. Take po = 900 kg/m³, pw = 1000 kg/m³, and PHg= 13550 kg/m³. 0.6 m 0.5 m B h'=0.3 m