When 1.022 g of anthracene, C14H10, is combusted in a bomb calorimeter that has a water jacket containing 500.0g of water, the temperature of the water increases by 25.65°C. Assuming that the specific heat of water is 4.18 J/(g "C), and that the heat absorption by the calorimeter is negligible, estimate the enthalpy of combustion per mole of anthracene (kJ/mol).

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### Estimation of the Enthalpy of Combustion of Anthracene

**Problem Statement:**

When 1.022 g of anthracene, \( \text{C}_{14}\text{H}_{10} \), is combusted in a bomb calorimeter that has a water jacket containing 500.0 g of water, the temperature of the water increases by 25.65°C. Assuming that the specific heat of water is 4.18 J/(g·°C), and that the heat absorption by the calorimeter is negligible, estimate the enthalpy of combustion per mole of anthracene (kJ/mol).

**Calculations:**

1. **Determine the heat absorbed by the water (\( q \)):**

\[ q = m \cdot c \cdot \Delta T \]

Where:
- \( m \) = mass of water (500.0 g)
- \( c \) = specific heat of water (4.18 J/(g·°C))
- \( \Delta T \) = temperature change (25.65°C)

\[ q = 500.0 \, \text{g} \cdot 4.18 \, \frac{\text{J}}{\text{g·°C}} \cdot 25.65 \, \text{°C} \]

2. **Convert the heat absorbed by the water to kilojoules (kJ):**

\[ q \text{(in kJ)} = q \text{(in J)} \times \frac{1 \, \text{kJ}}{1000 \, \text{J}} \]

3. **Determine moles of anthracene combusted:**

\[ \text{Moles of anthracene} = \frac{1.022 \, \text{g}}{\text{Molecular weight of } \text{C}_{14}\text{H}_{10}} \]

The molecular weight of anthracene (\( \text{C}_{14}\text{H}_{10} \)):

\[ 14 \times 12.01 \, \text{g/mol} + 10 \times 1.008 \, \text{g/mol} = 178.23 \, \text{g/mol} \]

4. **Convert the heat absorbed by the water to per mole of anthracene:**

\[ \
Transcribed Image Text:### Estimation of the Enthalpy of Combustion of Anthracene **Problem Statement:** When 1.022 g of anthracene, \( \text{C}_{14}\text{H}_{10} \), is combusted in a bomb calorimeter that has a water jacket containing 500.0 g of water, the temperature of the water increases by 25.65°C. Assuming that the specific heat of water is 4.18 J/(g·°C), and that the heat absorption by the calorimeter is negligible, estimate the enthalpy of combustion per mole of anthracene (kJ/mol). **Calculations:** 1. **Determine the heat absorbed by the water (\( q \)):** \[ q = m \cdot c \cdot \Delta T \] Where: - \( m \) = mass of water (500.0 g) - \( c \) = specific heat of water (4.18 J/(g·°C)) - \( \Delta T \) = temperature change (25.65°C) \[ q = 500.0 \, \text{g} \cdot 4.18 \, \frac{\text{J}}{\text{g·°C}} \cdot 25.65 \, \text{°C} \] 2. **Convert the heat absorbed by the water to kilojoules (kJ):** \[ q \text{(in kJ)} = q \text{(in J)} \times \frac{1 \, \text{kJ}}{1000 \, \text{J}} \] 3. **Determine moles of anthracene combusted:** \[ \text{Moles of anthracene} = \frac{1.022 \, \text{g}}{\text{Molecular weight of } \text{C}_{14}\text{H}_{10}} \] The molecular weight of anthracene (\( \text{C}_{14}\text{H}_{10} \)): \[ 14 \times 12.01 \, \text{g/mol} + 10 \times 1.008 \, \text{g/mol} = 178.23 \, \text{g/mol} \] 4. **Convert the heat absorbed by the water to per mole of anthracene:** \[ \
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