What you need to do: 1. Type that code up and run it to make sure that it is doing what it is supposed to do. Provide the strings in the header of the program when prompted. 2. Use the logic in that program to design your own Recursive Descent parser in C for the following grammar: S →aAB A →Abc | b B →d 3. Make sure that you choose at least two strings that pass the grammar and one string that does not pass the grammar just like I did in the model program 4. Submit both the code and a screen shot of your results for the choice of strings that you provided. Below is the C code that can be used to implement a Recursive Descent parser for the above grammar /* Recursive Descent Parser for the Expression Grammar: S → (L) |a L' →,SL'|ε L → SL' Valid inputs: (a,(a,a)) and (a,((a,a),(a,a))) Invalid inputs:(aa,a) */ #include #include int S(), Ldash(), L(); char *ip; char string[50]; int main() { printf("Enter the string\n"); scanf("%s", string); ip = string; printf("\n\nInput\t\tAction\n ------------------------------\n"); if (S()) { printf("\n------------------------------------------------\n"); printf("\n String is successfully parsed\n"); } else { printf("\n ------------------------------------------------\n"); printf("Error in parsing string\n"); } } int L() { printf("%s\t\tL →SL' \n", ip); if (S()) { if (Ldash()) { return 1; } else return 0; } else return 0; } int Ldash() { if (*ip == ',') { printf("%s\t\tL' →, SL' \n", ip); ip++; if (S()) { if (Ldash()) { return 1; } else return 0; } else return 0; } else { printf("%s\t\tL' →ε \n", ip); return 1; } } int S() { if (*ip == '(') { printf("%s\t\tS →(L) \n", ip); ip++; if (L()) { if (*ip == ')') { ip++; return 1; } else return 0; } else return 0; } else if (*ip == 'a') { ip++; printf("%s\t\tS →a \n", ip); return 1; } else return 0; }
What you need to do: 1. Type that code up and run it to make sure that it is doing what it is supposed to do. Provide the strings in the header of the program when prompted. 2. Use the logic in that program to design your own Recursive Descent parser in C for the following grammar: S →aAB A →Abc | b B →d 3. Make sure that you choose at least two strings that pass the grammar and one string that does not pass the grammar just like I did in the model program 4. Submit both the code and a screen shot of your results for the choice of strings that you provided. Below is the C code that can be used to implement a Recursive Descent parser for the above grammar /* Recursive Descent Parser for the Expression Grammar: S → (L) |a L' →,SL'|ε L → SL' Valid inputs: (a,(a,a)) and (a,((a,a),(a,a))) Invalid inputs:(aa,a) */ #include #include int S(), Ldash(), L(); char *ip; char string[50]; int main() { printf("Enter the string\n"); scanf("%s", string); ip = string; printf("\n\nInput\t\tAction\n ------------------------------\n"); if (S()) { printf("\n------------------------------------------------\n"); printf("\n String is successfully parsed\n"); } else { printf("\n ------------------------------------------------\n"); printf("Error in parsing string\n"); } } int L() { printf("%s\t\tL →SL' \n", ip); if (S()) { if (Ldash()) { return 1; } else return 0; } else return 0; } int Ldash() { if (*ip == ',') { printf("%s\t\tL' →, SL' \n", ip); ip++; if (S()) { if (Ldash()) { return 1; } else return 0; } else return 0; } else { printf("%s\t\tL' →ε \n", ip); return 1; } } int S() { if (*ip == '(') { printf("%s\t\tS →(L) \n", ip); ip++; if (L()) { if (*ip == ')') { ip++; return 1; } else return 0; } else return 0; } else if (*ip == 'a') { ip++; printf("%s\t\tS →a \n", ip); return 1; } else return 0; }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
What you need to do:
1. Type that code up and run it to make sure that it is doing what it is supposed to
do. Provide the strings in the header of the program when prompted.
2. Use the logic in that program to design your own Recursive Descent parser in C
for the following grammar:
S →aAB
A →Abc | b
B →d
3. Make sure that you choose at least two strings that pass the grammar and one
string that does not pass the grammar just like I did in the model program
4. Submit both the code and a screen shot of your results for the choice of strings
that you provided.
Below is the C code that can be used to implement a Recursive Descent parser for the above
grammar
/* Recursive Descent Parser for the Expression Grammar:
S → (L) |a
L' →,SL'|ε
L → SL'
Valid inputs: (a,(a,a)) and (a,((a,a),(a,a)))
Invalid inputs:(aa,a)
*/
#include <stdio.h>
#include <string.h>
int S(), Ldash(), L();
char *ip;
char string[50];
int main()
grammar
/* Recursive Descent Parser for the Expression Grammar:
S → (L) |a
L' →,SL'|ε
L → SL'
Valid inputs: (a,(a,a)) and (a,((a,a),(a,a)))
Invalid inputs:(aa,a)
*/
#include <stdio.h>
#include <string.h>
int S(), Ldash(), L();
char *ip;
char string[50];
int main()
{
printf("Enter the string\n");
scanf("%s", string);
ip = string;
printf("\n\nInput\t\tAction\n ------------------------------\n");
if (S())
{
printf("\n------------------------------------------------\n");
printf("\n String is successfully parsed\n");
}
else
{
printf("\n ------------------------------------------------\n");
printf("Error in parsing string\n");
}
}
int L()
{
printf("%s\t\tL →SL' \n", ip);
if (S())
{
if (Ldash())
{
return 1;
}
else
return 0;
}
else
return 0;
}
int Ldash()
{
if (*ip == ',')
{
printf("%s\t\tL' →, SL' \n", ip);
ip++;
if (S())
{
if (Ldash())
{
return 1;
}
else
return 0;
}
else
printf("Enter the string\n");
scanf("%s", string);
ip = string;
printf("\n\nInput\t\tAction\n ------------------------------\n");
if (S())
{
printf("\n------------------------------------------------\n");
printf("\n String is successfully parsed\n");
}
else
{
printf("\n ------------------------------------------------\n");
printf("Error in parsing string\n");
}
}
int L()
{
printf("%s\t\tL →SL' \n", ip);
if (S())
{
if (Ldash())
{
return 1;
}
else
return 0;
}
else
return 0;
}
int Ldash()
{
if (*ip == ',')
{
printf("%s\t\tL' →, SL' \n", ip);
ip++;
if (S())
{
if (Ldash())
{
return 1;
}
else
return 0;
}
else
return 0;
}
else
{
printf("%s\t\tL' →ε \n", ip);
return 1;
}
}
int S()
{
if (*ip == '(')
{
printf("%s\t\tS →(L) \n", ip);
ip++;
if (L())
{
if (*ip == ')')
{
ip++;
return 1;
}
else
return 0;
}
else
return 0;
}
else if (*ip == 'a')
{
ip++;
printf("%s\t\tS →a \n", ip);
return 1;
}
else
return 0;
}
}
else
{
printf("%s\t\tL' →ε \n", ip);
return 1;
}
}
int S()
{
if (*ip == '(')
{
printf("%s\t\tS →(L) \n", ip);
ip++;
if (L())
{
if (*ip == ')')
{
ip++;
return 1;
}
else
return 0;
}
else
return 0;
}
else if (*ip == 'a')
{
ip++;
printf("%s\t\tS →a \n", ip);
return 1;
}
else
return 0;
}
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