What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no products are removed)? C3H7OH+C2H5COOH=C6H12O2+H2O Percent yield of ester was 71.6% weight of product= 20.7868g 19.0mL (0.25mol) of n- propanol 18.5 mL (0.25 mol) of propionic acid At room temperature, the equilibrium constant, Keq is approximately 3.

What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no products are removed)? C3H7OH+C2H5COOH=C6H12O2+H2O Percent yield of ester was 71.6% weight of product= 20.7868g 19.0mL (0.25mol) of n- propanol 18.5 mL (0.25 mol) of propionic acid At room temperature, the equilibrium constant, Keq is approximately 3.

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability

Section: Chapter Questions

Problem 41PS

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