what would be the distance from the wire at which the field is measured if the current passes through a very long, thin, and straight wire is 3A and the magnetic field is 0.05mT

A pellet which holds a charge of 10 coulombs is moving upwards (+Y) and driven by an electric field in the same direction with a magnitude of 50 V/m. There is a magnetic field with a magnitude of 25 Tesla’s pointing downwards (-Y). How fast does the pellet need to be going for the magnetic force to cancel the electric force? Group of answer choices 0.5 m/s 2 m/s 4 m/s The forces will cancel out at any speed the pellet may be travelling In this case, the electric force cannot be canceled out by the magnetic force

A 1450 turn coil of wire, 6.16 cm in diameter, is in a magnetic field that drops from 0.723 T to 0 T in 41.9 ms. The axis of the coil is parallel to the field. What is the emf (in V) of the coil?

Given: B = 5 * 10-5 T ẑ; σ = 4 (Ohm-meters)-1 (conductivity) a) Assume that seawater is moving at a constant velocity v = v0 ŷ and that the Earth’s magnetic field is along the ẑ-direction. Calculate the electric current density J produced by the magnetic force. Hint: first compute the force per unit charge, F/q, and then use the relationship J = σ(F/q).  b) Derive the equation of motion of a cylindrical differential volume element of base area δA and height δh parallelto the direction of J. Assume that seawater has a known volumetric mass density ρ. Show that this equation implies that the velocity satisfies the following differential equation:dvy/dt = vy/τwhere τ is a constant that you should write in terms of B, σ, and ρ.

Crossed electric and magnetic fields have magnitudes of 4.65 V/m and 74.5 mT. Find the speed at which electrons moving perpendicular to both fields can travel through them without being deflected?

Shown in the figure below is a rectangle of wire immersed in a magnetic field. The rectangle has length L = 2 meters, width w = 2 meters, and a resistance of R = 7.97 Ω. The magnetic field varies with time according to the equation:B(t) = 5t2 + 2t5As a result of the varying field, a voltage and current will be established in the loop.Answer all of the following: What is the FORMULA for the rate of change of magnetic field with time,    dB dt    =        What is the FORMULA for the rate of change of magnetic flux with time,    dΦB dt    =        What is the voltage in the circuit at t=1.1 seconds?  Volts What is the current in the circuit at this same time?  Amps NOTE: Make all formulas POSITIVE (field and flux). Make all values POSITIVE (voltage and current). Format your equations as atn + btm where a,b,n,m are numerical values. Example: 12t2 + 72t3

MYMIVIVH uns w pui SIVIN IN WEHE saw piwa ISMIMIN 29. An electron is travelling at 100 km/s parallel to a long straight horizontal conductor a distance of 3.00 cm from the conductor. A current of 12.0 A runs through the wire as the electron travels parallel to it, in the same direction as the electron's velocity. Find the strength of the external electric field that will prevent the elec- tron from deviating from its original path. Express your answer in V/m.