What will the enolate for this be using LDA, THF, and cold temperatures?  What will it be using NaOEt at rt?

Q) can you show the step by step mechanism of these stating the neuclophiles and electrophiles and discussing the stereoselectivity? Why is that one has a higher yield then the other? Thank you

Is true about halohydrins, example bromohydrin the intermediate in a. the reaction mechanism is a cyclic halonium (bromonium) ion all b. alternatives are correct c.the product contains a halogen and an OH on adjacent carbons d. the nucleophile (H2O) attacks the most substituted carbon

Question 25 What reagents are needed to carry out the conversion shown? EtO Et Et Он O 1. HOCH2CH2CH3/H2SO4; 2. LIAIH4; 3. H3O* O 1. HOCH2CH2OH/H2SO4; 2. AICI3; 3. H30* О 1. НОСН2СН2ОН; 2. AICI3; 3. Нзо" O 1. HOCH2CH2CH2CH2OH; 2. LIAIH4; 3. H2SO4 O 1. HOCH2CH2OH/H2SO4; 2. LIAIH4; 3. H3O*

What will be in the HNMR of N,N-dimethylformamide (DMF), and ethyl acetate? Be clear and neat, please!

please draw a curved arrow mechanism for the folloeing reaction. please include all intermediate steps H -NR -BuMe₂SICI, Et3N, DMF (50% overall yield from L-aspartic acid (12)) -NH

Draw the organic product of the nucleophilic substitution reaction. Include all hydrogens atoms. CH3CH₂I + CH3CH₂O¯ → Select Draw Templates More //// C 0 H Erase Q2Q

In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 See Periodic Table O See Hint :ö: :Br: Add the missing curved arrow notation. 20 F CI Br I Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Keg > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e. Keg « 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg« 1) because bromide is a better leaving group than acetate.

Need help on this question. is it that they are in the same category because of the strong OH activator ?

In the anhydride compounds, the Sym stretching of the carbonyl groups Higher than Asym stretching .A O Smaller than Asym stretching .B O No relation between them.c O Equal.D O